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qwelly [4]
3 years ago
6

The diagonal of a TV is 42 inches. The base is 38 inches wide. How tall is the Tv? Round your answer to the nearest tenth. Put y

our answer in the box. EX: 10
Mathematics
2 answers:
Yuki888 [10]3 years ago
4 0

Answer:20.6 inches

Step-by-step explanation:

The diagonal measure of a rectangular TV screen is 42 inches. The width of the screen is 36.6 inches.

The diagonal , width and height forms a right angle triangle

So we apply pythagorean theorem

Diagonal is the hypotenuse

LEt the height of the screen is 'h'

c^2= a^2 + b^2

42^2= 36.6^2 + h^2

Subtract 36.6^2 from both sides

h^2 = 424.44

Take square root on both sides

h=20.60194

Round to nearest tenth

Height of the screen = 20.6 inches

iVinArrow [24]3 years ago
4 0

Answer:

1,600 inches

Step-by-step explanation:

You need to take the height of the tv and the base of the tv. So you need to take 42x38= 1,596. Now you need to round to the nearest tenth. So take 1,596 and the nearest tenth would be 1,600. Because 1,596 is closer to 1,596 then 1,590.

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The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa
horsena [70]

Answer:

7.2 years

Step-by-step explanation:

f(t) =200(1 - 0.956e^{-0.18t})

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So we plug in 148 for f(t) and solve for t

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divide both sides by 200

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Now subtract 1 from both sides

-0.26= - 0.956e^{-0.18t}

Divide both sides by -0.956

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Now take ln on both sides

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muminat

Answer:

y = 3/4 + 7

Step-by-step explanation:

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