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grin007 [14]
3 years ago
12

The elements cu, o, la, y, ba, tl, and bi are all found in high-temperature ceramic superconductors. write the expected electron

configuration for these atoms. (type your answer in noble gas notation using the format [ar] 4s2 3d10 4p3 for [ar] 4s2 3d10 4p3.)
Chemistry
1 answer:
timama [110]3 years ago
4 0
Part 1)
Cu- <span>[Ar] 3d¹⁰4s¹     </span><span>atomic number: 29
</span>
<span>O-  [He] 2s2 2p<span>4     atomic number:8

</span></span>La- <span>[Xe] 5d¹ 6s²      </span><span>atomic number:57

Y-   </span><span>[Kr] 4d¹5s²      </span><span>atomic number:39
 
Ba- </span><span>[Xe] 6s²      </span><span>atomic number:56

Tl-  </span><span>[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p¹   </span><span>atomic number:81

Bi- </span> <span>[Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³ </span>atomic number:83

Part 2)
You are able to this by consulting the periodic table and following this steps:
-Find your atom's atomic number;
<span>-Determine the charge of the atom (these were all uncharged)
</span><span>-Memorize the order of orbitals (s, d, p, d.. and how many electrons they can fit)
</span>-<span>Fill in the orbitals according to the number of electrons in the atom
- </span><span>for long electron configurations, abbreviate with the noble gases</span>




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In Na2O, what is the oxidation state of oxygen? In Na2O oxidation state of Na is 1+
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A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
Briefly explain formality in solution.
Zielflug [23.3K]

Answer:

Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.

4 0
3 years ago
If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
ValentinkaMS [17]

Answer:

M_{base}=0.173M

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

n_{acid}=M_{base}V_{base}

Thus, by solving for the volume of the base as NaOH, we obtain:

M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M

Best regards!

6 0
3 years ago
The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4 -2.
suter [353]

Answer:

The balanced equations for those dissociations are:

Ba(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻ (aq)

H₂SO₄ (aq) → 2H⁺(aq) + SO₄⁻²(aq)

Explanation:

As a strong base, the barium hidroxide gives OH⁻ to the solution

As a strong acid, the sulfuric acid gives H⁺ to the solution

Ba(OH)₂, is a strong base so the dissociation is complete.

H₂SO₄ is considerd a strong acid, but only the first deprotonation is strong.

The second proton that is released, has a weak dissociation.

H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

HSO₄⁻(aq) ⇄ H⁺ (aq) + SO₄⁻² (aq)       Ka

6 0
3 years ago
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