%C= 12/12 + 2·16=0,273=27,3%.
a. 35.8 KJ
b. 871 g
c. Fe
..........................................................................................
Answer:
32.8g/mole
Explanation:
Given parameters:
Mass of sample of gas = 32.8g
Volume = 22.4L
Unknown:
Molecular weight = ?
Solution:
To solve this problem we must understand that at rtp;
1 mole of gas occupies a volume of 22.4L
Number of mole of the gas = 1 mole
Now;
Mass = number of moles x molecular weight
molecular weight =
=
= 32.8g/mole