Question

You are watching a s Saturday morning cartoon concerning a jungle hero called George of the Jungle. George attempts to save a friend, an ape named Ape, from a stampeding herd of wildebeests. Ape is at the base of a tall tree which has a vine attached to its top. George is in another tree holding the other end of the vine. George plans to swing down from the tree, grab Ape at the bottom of the swing, and continue up to safety on a ledge which is half of George's initial height in the tree. Assuming that Ape weights the same as George, will they successfully make it to the top of the ledge? If you believe they do, how high a ledge could they make it to? If you disagree, suggest what could be done for George to save Ape.​

Answer 1

Answer:

I don't think so because if Ape was the same weight as george I don't

think he can hold him but maybe so let's say he could hold his own ape then Yes I think he could make it to the ledge Now I think they could make it to the ledge which was half the size.

Sorry if this sounded weird English is my 2nd language Oh and if this helped please give brainiest thank you <3

Answer 2

Answer:

No

Explanation:

Ignoring air resistance, George's velocity at the bottom of the swing is

½mv² = mgh

v = √(2gh)

conservation of momentum while George and Ape grab each other

m(√(2gh)) + m(0) = 2mv

v = ½√(2gh)

now the kinetic energy will convert back to potential energy

(2m)gh₂ = ½(2m)(½√(2gh))²

       gh₂ = ½(¼(2gh))

         h₂ = ¼h

so the two can only attain a height of one quarter of George's original height.

Ape could start running in the direction of George's swing so less momentum is lost during connection.