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atroni [7]
3 years ago
9

A battery is charging. Electric current enters the battery through the ______ terminal, at a ______ potential than when it exits

the battery
Physics
1 answer:
Agata [3.3K]3 years ago
6 0

Electric current enters the battery through the negative terminal, at a  high potential than when it exits the battery.

<h3>What is Potential difference?</h3>

This is the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.

In a battery, electric current moves from negative to the positive terminal with the positive terminal having a higher potential which is the point where it leaves the battery.

Read  more about Potential difference here brainly.com/question/87152

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An object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height abo
ki77a [65]

Answer:

11.09 m/s

Explanation:

Given that an object is thrown vertically up and attains an upward velocity of 9.6 m/s when it reaches one fourth of its maximum height above its launch point.

The parameters given are:

Initial velocity U = ?

Final velocity V = 9.6 m/s

Acceleration due to gravity g = 9.8m/s^2

Let first assume that the object is thrown from rest with the velocity U, at maximum height V = 0

Using third equation of motion

V^2 = U^2 - 2gH

0 = U^2 - 2 × 9.8H

U^2 = 19.6H ........ (1)

Using the formula again for one fourth of its maximum height

9.6^2 = U^2 - 2 × 9.8 × H/4

92.16 = U^2 - 19.6/4H

92.16 = U^2 - 4.9H

U^2 = 92.16 + 4.9H ...... (2)

Substitute U^2 in equation (1) into equation (2)

19.6H = 92.16 + 4.9H

Collect the like terms

19.6H - 4.9H = 92.16

14.7H = 92.16

H = 92.16/14.7

H = 6.269

Substitute H into equation 2

U^2 = 92.16 + 4.9( 6.269)

U^2 = 92.16 + 30.72

U^2 = 122.88

U = 11.09 m/s

Therefore, the initial velocity of the object is 11.09 m/s

3 0
3 years ago
The heat flux for a given wall is in the x-direction and given as q^n = 11 W/m^2, the walls thermal conductivity is 1.7 W/mK and
MrMuchimi

Answer:

\frac{dT}{dx} = 6.47 ^oC/m

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

Explanation:

As we know that heat flux is given by the formula

q^n = K\frac{dT}{dx}

here we know that

K = thermal conductivity

\frac{dT}{dx} = temperature gradient

now we know that

q^n = 11 W/m^2

also we know that

K = 1.7 W/mK

now we have

11 = 1.7 \frac{dT}{dx}

so temperature gradient is given as

\frac{dT}{dx} = \frac{11}{1.7} = 6.47 K/m

also in other unit it will be same

\frac{dT}{dx} = 6.47 ^oC/m

Also as we can see the equation that heat flux directly depends on the temperature gradient so more is the temperature gradient then more will be the heat flux.

For positive temperature gradient the heat will flow outwards while for negative temperature gradient the heat will flow inwards

5 0
3 years ago
Describe three risks or disadvantages of nuclear<br> power.
Galina-37 [17]

Answer:

due to the properties of radioactive elements like penetration power and ionization effect they can cause gene mutations, kill living cells and cause cancer. They also have the advantages. They are used to make nuclear energy

4 0
3 years ago
Read 2 more answers
Relativistic kinetic energy is conserved in all reference frames. True O False
Free_Kalibri [48]

Answer:

i think it is true

Explanation:

7 0
3 years ago
The normal is a line perpendicular to the reflecting surface at the point of incidence.
ladessa [460]

Answer:

True

Explanation:

The normal line is defined as the line which is perpendicular to the reflecting surface at the point where the incident ray meet with the reflecting surface.

The angle of incident is defined as the angle which is subtended by the incident ray with respect to the normal ray by consider the normal ray as the base line and angle is measured from the point where incident ray is incident on the reflecting surface of the mirror.

Similarly reflecting ray can be defined as the ray which is reflected after the incident of a ray and the angle subtended by the reflecting ray is measure with respect to normal ray by considering normal ray as a base line.

Therefore, the normal ray is the perpendicular line to the reflecting surface at the point of incidence.

4 0
3 years ago
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