Sodium chloride can be produced by the reaction of sodium metal with chlorine gas. Which is the limiting reactant if 6.70 moles
1 answer:
Answer:
Chlorine gas.
Explanation:
Hello!
In this case, the undergoing chemical reaction is:
Thus, given the moles of reacting both sodium and chlorine, we compute the moles of sodium chloride yielded by each reactant by considering the 2:2 and 1:2 mole ratios:
Thus, since chlorine yields less moles of sodium chloride, we infer it is the limiting reactant.
Best regards!
You might be interested in
Step 1 - Discovering the ionic formula of Chromium (III) Carbonate
Chromium (III) Carbonate is formed by the ionic bonding between Chromium (III) (Cr(3+)) and Carbonate (CO3(2-)):
Step 2 - Finding the molar mass of the substance
To find the molar mass, we need to multiply the molar mass of each element by the number of times it appears in the formula of the substance and, finally, sum it all up.
The molar masses are 12 g/mol for C; 16 g/mol for O and 52 g/mol for Cr. We have thus:
The molar mass will be thus:
Step 3 - Finding the percent composition of carbon
As we saw in the previous step, the molar mass of Cr2(CO3)3 is 284 g/mol. From this molar mass, 36 g/mol come from C. We can set the following proportion:
The percent composition of Carbon is thus 12.7 %.