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3 years ago

A 06-C charge and a .07-C charge are apart at 3 m apart. What force attracts them?

Physics

1 answer:

Burka [1]3 years ago

5 0

Answer:

the force of attraction between the two charges is 4.2 x 10⁹ N.

Explanation:

Given;

the magnitude of first charge, q₁ = 0.06 C

the magnitude of the second charge, q₂ = 0.07 C

distance between the two charges, r = 3 m

The force of attraction between the two charges is calculated as ;

$F = \frac{Kq_1q_2}{r^2}$

where;

k is Coulomb's constant = 9 x 10⁹ Nm²/C²

$F = \frac{Kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(0.06)(0.07)}{3^2} \\\\F = 4.2 \times 10^{6} \ N$

Therefore, the force of attraction between the two charges is 4.2 x 10⁹ N.

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What is thermal physics

viktelen [127]

Answer:

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Explanation:

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3 years ago

You are planning to make an open rectangular box from an 8-in.-by-15-in. piece of cardboard by cutting congruent squares from th

mariarad [96]

Should be 4x5x4!! If you take 8•15, you get 120!! There are six sides on a rectangular prism!! Thus leaving a value of 20 per side!! And I noted to properly equal out with the maximum volume it should mean 4•5=20!! Thus being 4•4•5

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3 years ago

What is the specific heat capacity of a 250g object that needs 34.125kJ to have its own temperature raised by 65.0∘C

Anestetic [448]

Answer:

Specific heat capacity, = 2.1J/g°C

Explanation:

Given the following data;

Mass = 250g

Quantity of heat = 34.125kJ = 34.125 * 1000 = 34125 Joules.

Change in temperature = 65.0∘C

To find the specific heat capacity;

Heat capacity is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making c the subject of formula, we have;

$c = \frac {Q}{mdt}$

Substituting into the equation, we have;

$c = \frac {34125}{250*65}$

$c = \frac {34125}{16250}$

Specific heat capacity, = 2.1J/g°C

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3 years ago

What type of phase change occurs when water vapor in the atmosphere changes to liquid water in clouds?

Mekhanik [1.2K]

Answer:

condensation, the process of changing from a gas to a liquid

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3 years ago

Find the radius RRigel of the star Rigel, the bright blue star in the constellation Orion that radiates energy at a rate of 2.7×

Lera25 [3.4K]

Answer:

$r=5.1\times10^{10}m$

Explanation:

The Stefan–Boltzmann law for a black body (as stars are treated) can be written as $j^*=\sigma T^4$ , where $j^*$ is the total energy radiated per unit surface area across all wavelengths per unit time, $T$ the absolute temperature and $\sigma=5.67\times10^{-8} Wm^{-2}K^{-4}$ is the Stefan–Boltzmann constant.

If we multiply $j*$ by the surface area $A$ of the star we get the total energy radiated across all wavelengths per unit time, which is the total power radiated, so we can write:

$P=Aj^*=A\sigma T^4=4\pi r^2\sigma T^4$

where we have used the formula for the surface area of a sphere $A=4\pi r^2$

Solving for r we have:

$r=\sqrt{\frac{P}{4\pi \sigma T^4}}=\sqrt{\frac{2.7\times10^{31}W}{4\pi (5.67\times^{-8}Wm^{-2}K^{-4})(11000K)^4}}=5.1\times10^{10}m$

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4 years ago