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Norma-Jean [14]
3 years ago
8

Which characteristic of the planets in our solar system increases as the distance from the sun increase?

Physics
1 answer:
Masja [62]3 years ago
5 0
Velocity increases as distance increase
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Which is gerrymandering a problem for the house of representatives but not the senate?
Fudgin [204]

Senators are elected in statewide elections rather than in specific districts. <em>(D)</em>

3 0
3 years ago
What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!
olya-2409 [2.1K]

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

5 0
4 years ago
A spring hangs from the ceiling with an unstretched length of x 0 = 0.35 m . A m 1 = 6.3 kg block is hung from the spring, causi
Jlenok [28]

Answer:

x₂=0.44m

Explanation:

First, we calculate the length the spring is stretch when the first block is hung from it:

\Delta x_1=0.50m-0.35m=0.15m

Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:

k\Delta x_1=m_1g

Solving for the spring constant k, we get:

k=\frac{m_1g}{\Delta x_1}\\\\k=\frac{(6.3kg)(9.8m/s^{2})}{0.15m}=410\frac{N}{m}

Next, we use the same relationship, but for the second block, to find the value of the stretched length:

k\Delta x_2=m_2g\\\\\Delta x_2=\frac{m_2g}{k}\\\\\implies \Delta x_2=\frac{(3.7kg)(9.8m/s^{2})}{410N/m}=0.088m

Finally, we sum this to the unstretched length to obtain the length of the spring:

x_2=0.35m+0.088m=0.44m

In words, the length of the spring when the second block is hung from it, is 0.44m.

3 0
4 years ago
The efficiency of a squeaky pulley system is 73 percent. The pulleys are usedto raise a mass to a certain height. What force is
larisa86 [58]

The efficiency of the machine is defined as

\eta = \frac{W_{out}}{W_{in}}

Here

Work out is the work output and Work in is the work input

To find the Work in we have then

W_{in} = \frac{W_{out}}{\eta}

W_{in} = \frac{mgh}{\eta}

Replacing with our values

W_{in} = \frac{(58)(9.8)(3)}{73\%}

W_{in} = 2335.89J

The work done by the applied force is

W = Fd

Here,

F = Force

d = Distnace

Rearranging to find F,

F = \frac{W}{d}

F = \frac{2335.89J }{18}

F = 129.77N

Therefore the force exerted on the machine after rounding off to two significant figures is 130N

8 0
3 years ago
Why might approaching an octopus cause a crab to start scurrying
liberstina [14]
Maybe the crab is scared or intimidated by the size of the octopus and tentacles
3 0
3 years ago
Read 2 more answers
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