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2 years ago

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Physics

2 answers:

Musya8 [376]2 years ago

8 0

Answer:

Decant it.

Explanation:

Pour the water/sugar solution off the sand. When the sand wants to start coming out as well, Stop and add fresh water to the beaker, stir to rinse the remaining solution into a less concentrated solution and decant again.

Repeat the dilution process until the mix is essentially sand and water, then drive the remaining water from the sand by drying.

egoroff_w [7]2 years ago

5 0

Strain it , the sand didn’t dissolve in the solution it just settled in the bottom

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A 2.72 A current flows through a wire for

agasfer [191]

Current=2.72A=I
Time=t=9.88s
Charge=Q

$\\ \rm\longmapsto I=\dfrac{Q}{t}$

$\\ \rm\longmapsto Q=It$

$\\ \rm\longmapsto Q=2.72\times 9.88$

$\\ \rm\longmapsto Q=26.87C$

8 0

3 years ago

A student uses a stopwatch to measure the period of the pendulum of the Beverly clock in the corridor. His measurements are: (a)

Westkost [7]

Answer:

Reading is close to (b) 13.44 which is the best estimate of the period

Associated error, $\Delta E =0.178 s$

Given:

$t_{a} = 13.54 s$

$t_{b} = 13.44 s$

$t_{c} = 13.89 s$

$t_{d} = 13.41 s$

$t_{e} = 13.17 s$

$t_{f} = 13.22 s$

Solution:

1.The best estimate of the period can be calculated by the mean of the measurements and the one closest to the mean is the best estimate of the measurement:

$Mean, \bar {x} = \fra{sum of all observations}{No. of observation}$

$Mean, \bar {x} = \frac{t_{a} + t_{b} + t_{c} +t_{d} + t_{e} + t_{f}}{6}$

$Mean, \bar {x} = \frac{13.54 + 13.44 + 13.89 + 13.41 + 13.17 + 13.22}{6}$

$Mean, \bar {x} = 13.445 s$

It is close to 13.44 s

2. Associated error is given by:

$\Delta E_{n} = |measured value - actual value|$

$\Delta E_{n} = |t_{n} - \bar {x}|$

where

n = a, b,......, e

Now,

$\Delta E_{a} = |t_{a} - \bar {x}| = |13.54 - 13.44| = 0.01$

$\Delta E_{b} = |t_{b} - \bar {x}| = |13.44 - 13.44| = 0.00$

$\Delta E_{c} = |t_{c} - \bar {x}| = |13.89 - 13.44| = 0.45$

$\Delta E_{d} = |t_{d} - \bar {x}| = |13.41 - 13.44| = 0.03$

$\Delta E_{e} = |t_{e} - \bar {x}| = |13.17 - 13.44| = 0.027$

$\Delta E_{f} = |t_{f} - \bar {x}| = |13.54 - 13.44| = 0.10$

Mean Absolute Error, $\Delta E = \frac{\Sigma E_{n}}{6}$

$\Delta E = \frac{0.01 + 0.00 + 0.45 + 0.03 +0.027 + 1.10}{6}$

$\Delta E =0.178 s$

3. The assumption behind the estimation is population is considered to distributed normally.

6 0

3 years ago

Suppose our Sun is about to explode. In an effort to escape, we depart in a spacecraft at v=0.800 c and head toward the star Tau

Levart [38]

Considering a scenario in which the Sun is going to explode.

In order to escape the explosion, we depart in a spacecraft with a speed of v = 0.8c.

The star Tau Ceti is 12 life years away.

At the midpoint of the journey, the Sun as well as Tau Cetik explode. at the same instant.

Imagine a hermit who is immobile with respect to both the Sun and Tau Ceti and resides on an asteroid that is midway between both. He observes the blast waves of both explosions as our spaceship passes him. This observer concludes that the two stars blew up simultaneously because he believes both stars to remain stationary.

In the frame of reference, the Sun and Tau Ceti explode at the same time and will remain stationary.

Learn more about the frame of reference here:

brainly.com/question/10962551

#SPJ4

8 0

2 years ago

In deep space there is very little friction once they are launched into a probe into deep space where there are no external forc

BabaBlast [244]

Continue on the momentum it has. The probe will continue in the same direction it is moving because there are no forces to act against it. I think this is the answer you are looking for...?

3 0

4 years ago

Read 2 more answers

Help me this question to solve

const2013 [10]

Answer:

1. 31 Ω

2. 42 Ω

3. V = IR

4. 4 A

5. 1.37 A

Explanation:

Sorry if I make any mistakes reading your handwriting. If I do, let me know and I'll fix it.

1. "Resistors of 5Ω, 10Ω, and 16Ω are connected in series. Find the total resistance."

The resistance of resistors in series is the sum:

R = R₁ + R₂ + R₃

R = 5Ω + 10Ω + 16Ω

R = 31Ω

2. "The total resistance of two resistors connected in series is 75Ω. The value of one resistor is 33Ω. What is the value of the other one?"

Since they are in series, the total resistance is the sum:

75Ω = 33Ω + R

R = 42Ω

3. "State Ohm's law."

Ohm's law states that a voltage drop across a resistor is equal to the resistance times the current.

V = IR

4. To find the current, we first find the total resistance, then use Ohm's law.

R = 10Ω + 15Ω + 30Ω

R = 55Ω

V = IR

220 V = I × 55Ω

I = 4 A

5. Same steps as before.

R = 1.5Ω + 4Ω + 12Ω

R = 17.5Ω

V = IR

24 V = I × 17.5Ω

I = 1.37 A

6 0

4 years ago

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!​

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!