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2 years ago

What are not examples of velocity

Physics

2 answers:

Nookie1986 [14]2 years ago

8 0

Answer:

Explanation:

Acceleration roughly means “change in velocity.” If this change in velocity is consistently in one direction, the body will reach a point at which its velocity is zero.

Another consideration is when you drop a basketball onto the pavement. The ball falls, hits the ground, and comes back up. Because its direction of motion changed, you know that its velocity MUST have been 0 m/s at some point during the bounce.

This doesn't mean there was no acceleration at this point.

maw [93]2 years ago

4 0

How long it takes to get somewhere

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A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0 N is requi

8_murik_8 [283]

Incomplete question as we have not told to find any quantity so I have chosen some quantities to find.So complete question is here

A 2.00-kg object is attached to a spring and placed on a frictionless, horizontal surface. A horizontal force of 20.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations.

Find (a) the force constant of the spring

(b) the frequency of the oscillations

Answer:

(a) $k=100N/m$

(b) $f=1.126Hz$

Explanation:

Given data

Mass of object m=2.00 kg

Horizontal Force F=20.0 N

Distance of the object from equilibrium A=0.2 m

To find

(a) Force constant of the spring k

(b) Frequency F of the oscillations

Solution

For (a) force constant of the spring k

From Hooke's Law we know that:

$F=kx\\k=F/x\\where\\x=A(amplitude)\\So\\k=F/A\\k=(20N/0.2000m)\\k=100N/m$

For (b) frequency F of the oscillations

The frequency of the motion for an object in simple harmonic motion is expressed as:

$f=\frac{1}{2\pi } \sqrt{\frac{k}{m} }\\ f=\frac{1}{2\pi } \sqrt{\frac{100N/m}{2.0kg} }\\f=1.126Hz$

For (c) maximum speed V of the object

For an object in simple harmonic motion the maximum values of the magnitude velocity is given as:

$v_{max}=wA\\ where\\w=\sqrt{\frac{k}{m} }\\ so\\v_{max}=\sqrt{\frac{k}{m} }A\\v_{max}=\sqrt{\frac{100N/m}{2.0kg} }(0.200m)\\v_{max}=1.41m/s$

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3 years ago

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prohojiy [21]

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2 years ago

Please answer 11-13. say if i'm right for 10 if you can.

brilliants [131]

The 2nd word on 11 is speed

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andrezito [222]

The final speed of the electron is 4.64 * 10^5 m/s.

<h3>What is the speed of the electron?</h3>

Given that the mass of the electron is obtained as 9.11 * 10^-31 Kg, we have that the charge of the electron is 1.6 * 10^-19 C.

E= F/q

F = Eq

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Using

v = u + at

u = 0 m/s because the electron was initially at rest

v = at

v = 5.8 * 10^13 * 8.00 ✕ 10−⁹ s

v = 4.64 * 10^5 m/s

Learn more about the speed of the electron:brainly.com/question/13130380

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1 year ago