Answer:
Explanation:
The momentum of an object is given by:
, where 
is the mass of the object and 
is the velocity of the object.
a)
The mass of the child and bike together is 
kilograms. Since they're moving at a velocity of 5.0 m/s, their momentum is:
.
b)
The mass of the child is given as 19 kg. Since the child is on the bike moving at 5.0 m/s, it's implied the child is as well. Therefore, the momentum of the child is:
.
c) The mass of the bike is given as 5.6 kg and it is moving at 5.0 m/s. Therefore, the momentum of the bike is:
<u />
<u />
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.
The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s
So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule
To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
Answer:
Periodic motion is a repetitious oscillation.
Explanation:
The time for one oscillation is the period T. The number of oscillations per unit time is the frequency f. These quantities are related by f=1T f = 1 T .
A golf ball<span> with a </span>mass<span> of 0.080kg initially at rest is given a speed of 50 m.s-1 ... When a </span>0.045 kg golf ball<span> takes off after being </span>hit<span>, its speed is 35 m/s. ... </span>golf<span> club with a </span>mass<span> of 250 g </span>travels<span> at 50 </span>meters per second hits<span> a 40 g </span>golf ball<span> and ... its speed is </span>41<span> m/s. a) What is the </span>kinetic energy<span> of the </span>ball<span> after it has been </span>hit<span>? hope it helps
</span>
Answer:
Situation one:
The moon will be experiencing gravitational force in the form of centripetal force, so we equate the two formulas.
Gravitational force = GMm /r²
Centripetal force = mv²/r
Equating,
GMm/r² = mv²/r
v² = GM/r
The first scenario will use the formula v² = GM/r
Situation 2:
The second situation will use the simple distance over time formula for velocity, where the distance will be the circumference and the time will be in seconds.
