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insens350 [35]
4 years ago
5

what is the desnity of a material that has 2500 grams and a volume of 500 cubic centimeters in grams per cubic centimeter

Physics
1 answer:
Ann [662]4 years ago
4 0
Divide 2500 g by 500 cc. The quotient is 5 g/cc ... the density.
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A 1250-kg car moves at 20.0 m/s. How much work must be done on the car to increase its speed to 30.0 m/s.
bulgar [2K]

Answer:

312,497.5Joules

Explanation:

Work done = force × distance

W = FS

Get the force

F = ma

F = 1250×9.8

F = 12250N

Get the distances using the equation of motion

v² = u² +2gS

30² =20²+2(9.8)S

900 =400+19.6S

900-400 =19.6S

500 = 19.6S

S = 500/19.6

S = 25.51m

Get the work done

Work done = 12250×25.51

Workdone = 312,497.5Joules

6 0
3 years ago
Seeing light coming out from a crack in the wall is what type of wave interaction?
Norma-Jean [14]

Answer:

C

becuase its where a wave (light etc) goes through a narrow area or across an edge of an area

3 0
3 years ago
Why is there no overall electrical charge on an aluminium atom?
uranmaximum [27]
The electrical charge of particles. The total number of electrons in an atom is always the same as the number of protons in the nucleus. This means atoms have no overall electric charge. The number of protons in an atom is called its atomic hater number.
4 0
3 years ago
Read 2 more answers
"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66
Kamila [148]

Answer:

56°

Explanation:

Brewsters angle can be simply derived from

n1sin theta1= n2sintheta2= n2costheta1

because the reflected light will be 100% polarized if it is reflected at an angle 90o to the refracted light. Hence, Brewsters angle is

Tan theta= n2/n1

1.66/1.11= 1.495

Theta = 56°

Explanation:

7 0
3 years ago
How to do this, i'm completely lost
vaieri [72.5K]
There are two torques t1 and t2 on the beam due to the weights, one torque t3 due to the weight of the beam, and one torque t4 due to the string.

You need to figure out t4 to know the tension in the string.

Since the whole thing is not moving t1 + t2 + t3 = t4.

torque t = r * F * sinФ = distance from axis of rotation * force * sin (∡ between r and F)

t1 =3.2 * 44g 
t2 = 7 * 49g 
t3 = 3.5 * 24g 

t4 = t1 + t2 + t3 = 5570,118

The t4 also is given by:

t4 = r * T * sin Ф

r = 7
Ф = 32°
T: tension in the string

T = t4 / (r * sinФ)

T = t4 / (7 * sin(32°)) 

T = 1501,6 N

8 0
4 years ago
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