Answer:
Diameter of Newton’s 5th ring = 0.30 cm
Diameter of Newton’s 15th ring = 0.62 cm
Diameter of Newton’s 25th ring = ?
From Newton’s rings experiment we infer that
D2n+m − D2n = 4λmR
For the 5th and 15th rings we have
D215 − D25 = 4λ * 10 * R _______ (1) (m = 10)
For 15th and 25th rings
D225 − D215 = 4λ * 10 * R _______ (2) (m = 10)
We equate the two derivatives
Equation (2) = Equation (1)
D225 − D215 = D215 − D25
D225 = 2D215 – D25
Substituting the values into the equation
D225 = 2 * 0.62 * 0.62 – 0.3 * 0.3 =0.6788 cm2
D25 = 0.8239 cm
Answer:
a = 3.27 m/s²
v = 2.56 m/s
Explanation:
given,
mass A = 1 kg
mass B = 2 kg
vertical distance between them = 1 m
![F_d = mg](https://tex.z-dn.net/?f=F_d%20%3D%20mg)
![F_d = 2 \times 9.8](https://tex.z-dn.net/?f=F_d%20%3D%202%20%5Ctimes%209.8)
![F_d = 19.6\ N](https://tex.z-dn.net/?f=F_d%20%3D%2019.6%5C%20N)
![F_u = mg](https://tex.z-dn.net/?f=F_u%20%3D%20mg)
![F_u = 1 \times 9.8](https://tex.z-dn.net/?f=F_u%20%3D%201%20%5Ctimes%209.8)
![F_u = 9.8\ N](https://tex.z-dn.net/?f=F_u%20%3D%209.8%5C%20N)
![F_{net} = 19.6 - 9.8](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%2019.6%20-%209.8)
![F_{net}=9.8\ N](https://tex.z-dn.net/?f=F_%7Bnet%7D%3D9.8%5C%20N)
![F = (m_1+m_2)a](https://tex.z-dn.net/?f=F%20%3D%20%28m_1%2Bm_2%29a)
![9.8 = (2+1)a](https://tex.z-dn.net/?f=9.8%20%3D%20%282%2B1%29a)
a = 3.27 m/s²
The speed of the system at that moment is:
v² = u² + 2×a×s
v² = 0² + 2× 3.27 × 1
v ² = 6.54
v = 2.56 m/s
7.17m/s glad I could help
First I will parallel two of the resistors, creating a net 1 ohm. Then I will series that with the remaining 2-ohm resistor, resulting in 3 ohms.
Answer:
General intelligence refers to the existence of a broad mental capacity that influences performance on cognitive ability measures.
Specific intelligence refers to a person's aptitude in individual 'modalities' or abilities rather than the more general understanding of intelligence.
Explanation: