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ololo11 [35]
4 years ago
9

Which of the statements below about buoyancy is true?

Physics
1 answer:
Makovka662 [10]4 years ago
4 0
<span>A. The buoyant force only acts on objects in water. - The buoyant force can act in ANY liquid, not just water

B. The buoyant force is always stronger than the force of gravity. - This is false.  The buoyant force is dependent on the size of the object and not gravity

C. The buoyant force causes objects to sink more quickly than 9.8 m/s2. - This is false, since the buoyant force ALWAYS acts opposite of gravity.

D. The buoyant force always pushes objects up towards the surface of the fluid. - This is true</span>
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A student pushes a 50-N box across the floor a distance of 15 m. How much work was done to move the box?
irinina [24]

Answer:750

Explanation:

50 times 15

4 0
3 years ago
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With what minimum speed must you toss a 200 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release
Brut [27]
When they say use energy, you want to use

Total energy = potential energy + kinetic energy = mgh + 1/2mv²

I assume you mean 200 g ball,

so, we know the total distance traveled is going to be 13 - 1.3 = 11.7 m

If the ball just makes it to the top ( 13 m ) , then the ball will stop moving and the kinetic energy will be 0,

therefore, the potential energy at the top will be the total energy of the system = mgh

from this, we say that mgh = 1/2mv² solve for v

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8 0
4 years ago
Would the frequency of the angular simple harmonic motion (SHM) of the balance wheel increase or decrease if the dimensions of t
storchak [24]

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

T=2\pi\sqrt{\frac{I}{K}}

I=mR^{2}

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}

As dimensions of new balance wheel are one-third of their original values

R_{new}=\frac{R}{3}

\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega

5 0
3 years ago
A ball rolls down a hill and hits a box. The momentum of the ball decreases. Which happens to the momentum? Select one of the op
Irina-Kira [14]
<span>So we want to know what happens to the momentum of the ball that rolls down hill and hits a box. So we need to use the law of conservation of momentum which states that the momentum must be conserved. It cant be transformed into inertia or mass. It can only be transferred to other object via some interactions like collisions. So it has to be a. transferred to the box and that is the correct answer. </span>
7 0
3 years ago
It requires 3480 J to move a 675 N object how far?
goblinko [34]
5.16 meters!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
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