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3 years ago

Examples of conduction

Chemistry

1 answer:

Sonja [21]3 years ago

3 0

Answer:

Conduction: Touching a stove and being burned. Ice cooling down your hand. Boiling water by thrusting a red-hot piece of iron into it.

Explanation:

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Can someone solve this a put all 3 steps ?

Stolb23 [73]

Answer:

I think the height should be 0.17m

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3 years ago

- Calculate the Standard Enthalpy of the reaction below:

ANEK [815]

Answer:

Explanation:

We have the three equations:

$NH_{3(g)} + HCl_{(g)} => NH_4Cl_{(s)} ..... \Delta H = ? (1)\\2HCl_{(g)} => H_{2(g)} + Cl_{2(g)} .... \Delta H = +184.6 kJ (2)\\2H_{2(g)} + 1/2N_{2(g)} + 1/2Cl_{2(g)} => NH_4Cl_{(s)} ..... \Delta H = -314.2 kJ (3)\\ N_{2(g)} + 3H_{2(g)} => 2NH_{3(g)} .... \Delta H = +184.6kJ (4)$

(can you double check that it is 184.6kJ for both equations 2 and 4 because it seems unlikely). We need to solve for equation 1 by addition and changing equations 2, 3 and 4. After possibly some trial and error, we can find that if we flip equations 4, multiply equation 3 by 2, add the equations together, and then finally divide by 2, we can get equation 1. We will get the answer of -314.2 kJ. However, I am again skeptical about the delta H values for equation 2 and 4 so double check that. This method might be super confusing and it is really hard to explain. So what I would suggest you to watch videos on Hess' law.

3 0

3 years ago

How many molecules of F2 in 90g F2

Bogdan [553]

I dont know good luck!

7 0

3 years ago

How much energy is released by the decay of 3 grams of 20Th in the following reaction 230 Th - 226Ra + 'He (230 Th = 229.9837 g/

wolverine [178]

Answer : The energy released by the decay of 3 grams of 'Th' is $2.728\times 10^{-15}J$

Explanation :

First we have to calculate the mass defect $(\Delta m)$ .

The balanced reaction is,

$^{230}Th\rightarrow ^{226}Ra+^{4}He$

Mass defect = Sum of mass of product - sum of mass of reactants

$\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

conversion used : $(1amu=1.66\times 10^{-27}kg)$

Now we have to calculate the energy released.

$Energy=\Delta m\times (c)^2$

$Energy=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$Energy=2.0916\times 10^{-13}J$

The energy released is $2.0916\times 10^{-13}J$

Now we have to calculate the energy released by the decay of 3 grams of 'Th'.

As, 230 grams of Th release energy = $2.0916\times 10^{-13}J$

So, 3 grams of Th release energy = $\frac{3}{230}\times 2.0916\times 10^{-13}J=2.728\times 10^{-15}J$

Therefore, the energy released by the decay of 3 grams of 'Th' is $2.728\times 10^{-15}J$

5 0

4 years ago

The two esters below are synthesized from the starting material below. identify and draw the neutral reagent that is missing.

schepotkina [342]

The two Esters along with starting materials are shown below. The missing reagents ate shown in Blue encircled in red box. First reaction is carried out in acid which increases the reactivity of carboxylic acid (electrophilicity odf carbonyl carbon). And second reaction is carried out in the presence of Base, which increases the Nucleophilicity of nucleophile i.e. Alcohols.

4 0

4 years ago