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SVEN [57.7K]
3 years ago
11

Write a nuclear equation to represent radium-226 decaying to radon-222 plus an alpha particle.

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0
Answer:

<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>

Explanation:

An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.

Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation:

<span><span>22688</span>Ra→<span>l<span>22286</span></span>Rn+<span>l<span>42</span></span>He</span>

Note that the sum of the subscripts (atomic numbers or charges) is the same on each side of the equation.

Also, the sum of the superscripts (masses) is the same on each side of the equation.

Now try figuring out Am-241

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How many grams are there in 3.30x10 23 grams of n2i6
qwelly [4]
Technically, the answer should be 3.30 * 10^23 grams. But I think you mean either molecules, atoms, moles or grams of Ni2I6 with that number of molecules .

1 mole of Ni2 I6  = 6.02 * 10^23 molecules
x  [mole] = 3.30 * 10^23 molecules

1/x = 6.02 * 10^23 / 3.30 * 10^23 Cancel the 10^23 on the right side
1/x = 6.02 / 3.30 Cross multiply
3.30 = 6.02 x Divide by 6.02
3.30 / 6.02 = x 
x = 0.548 moles 

what to do from here?

1 mole of Ni2I6 is
2 * Ni = 2 * 59 = 118 grams
6 *  I = 6 * 131 = <u>786 grams</u>
Total  =               904 grams

Set up a proportion.
<u>1 mole Ni2I6 </u>  = <u>904 grams</u>  
0.548 moles    = x

1/0.548 = 904/x Cross multiply
x = 0.548 * 904
x = 495.4 grams of Ni2I6 <<<<<< Answer.

8 0
3 years ago
Calculate the empirical formula of each of the following substances with the following compositions.
OleMash [197]

Explanation:

Note: Molar masses of elements can be found online or in the periodic table.

Moles of Magnesium

= 3.60g / (24.3g/mol) = 0.148mol.

Moles of Chlorine

= 10.65g / (35.45g/mol) = 0.300mol.

Mole ratio of Magnesium to Chlorine

= 0.148mol : 0.300mol = 1 : 2.

Hence we have the empirical formula MgCl2.

Moles of Lithium

= 9.1g / (6.94g/mol) = 1.311mol.

Moles of Oxygen

= 10.4g / (16g/mol) = 0.650mol.

Moles ratio of Lithium to Oxygen

= 1.311mol : 0.650mol = 2 : 1.

Hence we have the empirical formula Li2O.

7 0
2 years ago
What is the number of moles of solute in a .3 molality solution containing .10 kg of solvent?
denpristay [2]
Concentration can be expressed in different forms: molarity, molality, normality, percentage, part per million and many more. For molality, it is a unit of concentration expressed as moles of solute per kilogram of solvent. Therefore,

0.3 = moles solute/0.10 kg solvent
moles solute = 0.03 moles
4 0
3 years ago
Read 2 more answers
Describe the whole process of Aluminum extraction from bauxite.​
AlekseyPX

Answer:

Extraction of aluminium

Aluminium ore is called bauxite . The bauxite is purified to produce aluminium oxide, a white powder from which aluminium can be extracted. The extraction is done by electrolysis. The ions in the aluminium oxide must be free to move so that electricity can pass through it.

4 0
2 years ago
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What is the number of moles in 546 g strontium nitrite?
Eduardwww [97]
The answer is 2.58 mol
4 0
2 years ago
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