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zhannawk [14.2K]
3 years ago
9

Could someone please help me??

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0

7.9×10^-1 Kg/m³

or, 0.79 Kg/m³

Hope it helps you...

zloy xaker [14]3 years ago
8 0

Answer:

okay in converting g to kg divide my 1000 and in converting cm³ to m³ divide by 1000000

7.9 x 10^-4 g/cm³ to kg/m³

we divide by 1000 and at the same time by 1000000

so that gives 1000000/1000 (it flips)

so we have 7.9 x 10^-4 x 1000000/1000

that gives 7.9 x 10 ^-1 kg/m³

which is 0. 79 kg/m³

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Will mark the brainiest later for correct answers! Please show work.
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Answer:

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To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
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2 years ago
Calculate the thermometer in an air-conditioned room reads 20.0°C what is the temperature of the room In degrees Fahrenheit and
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Answer:

A. 68°F

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Explanation:

The temperature (celsius) = 20.0°C

A. Conversion of the temperature in celsius to fahrenheit.

This is illustrated below:

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C = 20°C

°F = 9C/5 + 32

°F = 9x20/5 + 32

°F = 36 + 32

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AVprozaik [17]

Answer:

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Explanation:

First we <u>convert 750.0 mL into L</u>:

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Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:

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