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RSB [31]
3 years ago
14

The mixing of which pair of reactants will result in a precipitation reaction?

Chemistry
1 answer:
Maru [420]3 years ago
8 0

Answer:

K2SO4(aq) + Ba(NO3)2(aq)

Explanation:

K2SO4(aq) + Ba(NO3)2(aq)= 2KNO3(aq) + BaSO4(s)

The reaction produces BaSO4

Which precipitates as the insoluble product and Soluble KNO3 solution

You might be interested in
Suppose a liquid level from 5.5 to 8.6 m is linearly converted to pneumatic pressure from 3 to 15 psi. What pressure will result
wlad13 [49]

Answer:

a) P = 9.58 psi for  h=7.2 m

b) P=4.7 psi for h=5.94 m

Explanation:

Since the pressure Pon a static liquid level h is

P= p₀ + ρ*g*h

where p₀= initial pressure , ρ=density , g = gravity

then he variation of the liquid level Δh will produce a variation of pressure of

ΔP= ρ*g*Δh → ΔP/Δh =  ρ*g = ( 15 psi - 3 psi) /( 8.6 m - 5.5 m)  = 12/3.1 psi/m

if the liquid level is converted linearly

P = P₁ + ΔP/Δh*(h -h₁)

therefore choosing  P₁ = 3 psi and h₁= 5.5 m , for h=7.2 m

P = 3 psi  + 12/3.1 psi/m *(7.2 m -5.5 m) = 9.58 psi

then P = 9.58 psi for  h=7.2 m

for P=4.7 psi

4.7 psi = 3 psi  + 12/3.1 psi/m *(h -5.5 m)

h = (4.7 psi - 3 psi)/ (12/3.1 psi/m) + 5.5 m = 5.94 m

then P=4.7 psi for h=5.94 m

5 0
3 years ago
How many moles are in 10 mg of NO2
podryga [215]

mole=10 x 10⁻³ : 46 g/mol = 2.17 x 10⁻⁴

4 0
2 years ago
Read 2 more answers
A gas occupies a volume of 160 ml at 36° C and 970mm Hg. What is the volume at STP?
igor_vitrenko [27]

Answer:

I'm sorry I just need points

Explanation:

7 0
2 years ago
How many grams of CO₂ can be produced from the combustion of 2.76 moles of butane according to this equation: 2 C₄H₁₀(g) + 13 O₂
Vilka [71]

Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

Combustion reaction:

2 C₄H₁₀(g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (g)

If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

2 moles of butane can produce 8 moles of dioxide

Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

We convert the moles to mass → 11.04 mol . 44g / 1 mol = 485.76 g

5 0
3 years ago
What are the rules for naming covalent compounds
arsen [322]
<span>1.Remove the ending of the second element, and add "ide" just like in ionic compounds
 2.When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound
3.If there is only one of the first element, you can drop the prefix
<span>4.If there are two vowels in a row that sound the same once the prefix is added (they "conflict"), the extra vowel on the end of the prefix is removed</span></span>
6 0
3 years ago
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