Question

nitial mass of water, at its boiling point, is 0.8 kg. 4 kW of heater is used to boil it completely. Assuming the specific latent heat of vaporization of water is 2MJ/kg, what is the time taken to vaporize all the water

Answer 1

The  time taken to vaporize all the water is 400 seconds.

Total heat required to vaporize the water

The total heat required to vaporize the water is calculated as follows;

E = Lm

where;

• L is latent heat of vaporization of water
• m is mass of water

E  = 2 x 10⁶ J/kg x 0.8 kg

E = 1,600,000 J

Time taken to vaporize all the water

The time taken to vaporize all the water is calculated as follows;

E = power x time

time = E/power

time = ( 1,600,000 J) / (4,000 J/s)

time = 400 seconds

Thus, the  time taken to vaporize all the water is 400 seconds.

Learn more about heat of vaporization of water here: brainly.com/question/26306578

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