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IrinaVladis [17]
2 years ago
7

nitial mass of water, at its boiling point, is 0.8 kg. 4 kW of heater is used to boil it completely. Assuming the specific laten

t heat of vaporization of water is 2MJ/kg, what is the time taken to vaporize all the water
Chemistry
1 answer:
asambeis [7]2 years ago
6 0

The  time taken to vaporize all the water is 400 seconds.

<h3>Total heat required to vaporize the water</h3>

The total heat required to vaporize the water is calculated as follows;

E = Lm

where;

  • L is latent heat of vaporization of water
  • m is mass of water

E  = 2 x 10⁶ J/kg x 0.8 kg

E = 1,600,000 J

<h3>Time taken to vaporize all the water</h3>

The time taken to vaporize all the water is calculated as follows;

E = power x time

time = E/power

time = ( 1,600,000 J) / (4,000 J/s)

time = 400 seconds

Thus, the  time taken to vaporize all the water is 400 seconds.

Learn more about heat of vaporization of water here: brainly.com/question/26306578

#SPJ1

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A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydro
lutik1710 [3]
  • The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
  • That is approximately 0.001758.
  • Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
  • The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.
<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>
  • Consequently, we are aware that magnesium and chloride react.
  • We create 1 as the reaction ratio is 1:2.
  • The hydrogen and 1 are more.
  • Magnesium chloride is more.
  • Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
  • Among hydrogen, there is.
  • \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
  • The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
  • Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
  • So, in this instance, we are aware that p v = n r t.
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  • Let's proceed with the calculations right now.
  • In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

To learn more about Magnesium chloride reactions visit:

brainly.com/question/27891157

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3 0
2 years ago
Santiago's car has an overall average speed of 25 cm/s. If he could increase his car's overall average speed by 10%, what would
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Given:

The overall average speed = 25 cm/s.

The overall average speed increased by 10%.

To find:

The new overall average speed.

Solution:

We have,

Overall average speed = 25 cm/s.

The overall average speed increased by 10%. So, the new average speed is

New overall average speed = Initial average speed + 10% of initial  overall average speed

\text{New overall average speed}=25+\dfrac{10}{100}\times 25

\text{New overall average speed}=25+2.5

\text{New overall average speed}=27.5

Therefore, the new overall average speed is 27.5 cm/s.

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Balance the following half-reaction: (acidic) NO−3(aq) → NO2(aq) Express your answer as a half-reaction. Identify all of the pha
Marrrta [24]

Answer:

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Explanation:

NO₃⁻  →  NO₂

In left side, Nitrogen acts with +5 by oxidation number

In right side, the oxidation number is +4

This is a reduction reaction, because the oxidation number has decreased. So the N has gained electrons.

NO₃⁻  + 1e⁻ →  NO₂

In acidic medium, we have to add water, where there are less oxygens to ballance the amount. We have 2 O in left side, and 3 O in right side, so we have to add 1 H₂O on left side.

NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Now that oxygens are ballanced, we have to ballance the hydrogens by adding protons in the opposite side

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

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The refractory period makes the cell rest. In this period, the cell becomes able to depolarize again by collecting ions.
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Some symptoms are:

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