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o-na [289]
3 years ago
5

Identify the following reaction type using the chemical equation below*

Chemistry
1 answer:
OLEGan [10]3 years ago
3 0

Answer:

its C. a combustion reaction

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Mole used in a chemistry sentence
katrin [286]
One mole of NaOH (Sodium hydroxide) is equal to 39.997 grams of NaOH. 
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3 years ago
How many grams of perchloric acid, HClO4, are contained in 39.1 g of 74.9 wt% aqueous perchloric acid
Leno4ka [110]

Answer:

29.3 g HClO₄

Explanation:

We have 39.1 grams of 74.9 wt% aqueous perchloric acid solution, that is, there are 74.9 grams of perchloric acid in 100 grams of perchloric acid solution. The mass, in grams, of perchloric acid contained in 39.1 grams of perchloric acid solution is:

39.1 g Solution × (74.9 g HClO₄/100 g Solution) = 29.3 g HClO₄

5 0
3 years ago
Describe two ways in which sodium chloride is different from sodium​
KATRIN_1 [288]

Answer:

sodium chloride is a component is a salt made of a metal Sodium and a non chlorine is a alone only and element and very less stable until bonded with them metal like a n, a, k or H

7 0
3 years ago
A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe
Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

8 0
3 years ago
What is the name of this hydrocarbon? 2–methylpentyne 2–dimethylpentene 2,3–dimethylpentane 3,2–dimethylpentane
Phantasy [73]
<span>on plato it's 2,3–dimethylpentane

</span>
6 0
3 years ago
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