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2 years ago

The handle of a hammer is 20 cm long and the metal end pulls

Physics

1 answer:

artcher [175]2 years ago

6 0

Answer:

Given the experimental setup shown below, where should you put object C, ... applies a force of 150 N. What is the mechanical advantage of the hammer? ... Explain why tin snips, designed for cutting metal, have long handles and short blades. ... advantage for scissors, a first-class lever, is the length of the handle divided ...

Explanation:

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The brakes application to a car produce an acceleration of 6ms2 in the opposite direction to the motion .If the car takes 2 seco

Anna [14]

Answer:12 meter

Explanation:

acceleration(a)=6m/s^2

Time(t)=2 seconds

Distance =(a x t^2)/2

Distance =(6 x 2^2)/2

Distance=(6 x 2 x 2)/2

Distance=24/2

Distance =12

Distance is 12 meters

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2 years ago

In your own words, define the following terms.<br> 2. climate___________.

qwelly [4]

Answer:

The state of a certain type of land or a biome.

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1 year ago

Which type of communications equipment functions as a radio receiver and searches across several frequencies?

krok68 [10]

A <u>scanner</u> is a type of communications equipment that functions as a radio receiver and searches across several frequencies.

A scanner is a kind of a radio receiver that has the ability to receive multiple signals.

There are three modes which a scanner uses for acting as a radio receiver. The scan mode of the radio receiver constantly changes frequencies that helps in transmissions. There is also a manual scan mode that allows the users to search for their interested frequencies. The search mode allows the users to search through two sets of frequencies.

A scanner is a type of communication equipment that is easy to use with various features such as the volume, numeric keypad, trunk tracking etc.

To learn more about scanners, click here:

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7 0

1 year ago

What is the net work on the block?

Strike441 [17]

Answer:

A block device is a computer data storage device that supports reading and (optionally) writing data in fixed-size blocks, sectors, or clusters. These blocks are generally 512 bytes or a multiple thereof in size

8 0

2 years ago

A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f

Hitman42 [59]

(a) The angular acceleration of the wheel is given by
$\alpha = \frac{\omega_f - \omega_i }{t}$
where $\omega_i$ and $\omega_f$ are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
$\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2$

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
$\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2$
where $\omega_i = 0$ is the initial angular speed. So, the angle covered after a time t=3.07 s is
$\theta= \frac{1}{2} \alpha t^2 = \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad$

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2 years ago