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Llana [10]
2 years ago
13

The acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec​

Physics
1 answer:
jenyasd209 [6]2 years ago
4 0

Answer:

4 m/s^2

Explanation:

The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).

Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.

In our case:

Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s

Δt = 9s

a = Δv/Δt = 36m/s / 9s = 4m/s^2

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