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natta225 [31]
3 years ago
15

A box of bananas weighing 40 N rests on a horizontal surface. The coefficient of static friction between the box and the surface

is 0.4, and the coefficient of kinetic friction is 0.2. If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box?
8 N


16 N


6 N


0 N
Physics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

0.4x40 \div 0.2 = 80

8N

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
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Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

          \lambda_1  = 574.2 nm

at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

          \lambda_ 1 =  574.2 nm

           

6 0
4 years ago
The force in Newtons on a particle directed along the x-axis is given by F(x)=exp(−(x/2)+6) for x≥0 where x is in meters. The pa
HACTEHA [7]

To find the work done on the particle, the following is the solution:

Dw = F dx

W = integral over the path ( F(x) dx)

W = integral from 0 to 1 (e^(-x/5 + 5) dx)

W = -5e^(-x/5 + 5) from 0 to 1

W = 135 J

The work done is 135 J.

3 0
3 years ago
The transfer of energy carried in rays is called convection true or false
Oxana [17]
False that is radiation
4 0
3 years ago
For the population, scores on the test are normally distributed with μ = 70 and σ = 15. The sample of n = 25 students had a mean
AysviL [449]

Answer:

z=\frac{75-70}{\frac{15}{\sqrt{25}}}=1.67      

p_v =2*P(t_{24}>1.67)=0.108  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significant different from 70.    

Explanation:

1) Data given and notation      

\bar X=75 represent the sample mean

\sigma=15 represent the standard deviation for the population

n=25 sample size      

\mu_o =70 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is different from 70, the system of hypothesis would be:      

Null hypothesis:\mu = 70      

Alternative hypothesis:\mu \neq 70      

We know the population deviation, so for this case is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:      

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

z=\frac{75-70}{\frac{15}{\sqrt{25}}}=1.67      

Calculate the P-value      

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test the p value would be:      

p_v =2*P(t_{24}>1.67)=0.108  

Conclusion      

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significant different from 70.      

3 0
4 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

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  • speed at lowest point = V1
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  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
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      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
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