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natta225 [31]
2 years ago
15

A box of bananas weighing 40 N rests on a horizontal surface. The coefficient of static friction between the box and the surface

is 0.4, and the coefficient of kinetic friction is 0.2. If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box?
8 N


16 N


6 N


0 N
Physics
1 answer:
ale4655 [162]2 years ago
3 0

Answer:

0.4x40 \div 0.2 = 80

8N

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a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

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8 0
1 year ago
Help! I don’t really know what it’s asking
Misha Larkins [42]
You have to do the math of each and see which one adds up to 66.5
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What is the process called when the moon begins to fade from a full moon to the new moon?
satela [25.4K]

Answer: Waning

Explanation: Not much explanation for this

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3 years ago
A 0.12 kg body undergoes simple harmonic motion of amplitude 8.5 cm and period 0.20 s. (a) What is themagnitude of the maximum f
Neporo4naja [7]

Answer:

a)F=698.83 N

b)K=8221.56 N/m

Explanation:

Given that

mass ,m = 0.12 kg

Amplitude ,A= 8.5 cm

time period ,T = 0.2 s

We know that

T=\dfrac{2\pi}{\omega}

{\omega}=\dfrac{2\pi }{0.2}\ rad/s

{\omega}=31.41\ rad/s

We know that

{\omega}^2=m\ K

K=Spring constant

K=\dfrac{\omega^2}{m}

K=\dfrac{31.41^2}{0.12}\ N/m

K=8221.56 N/m

The maximum force F

F= K A

F= 8221.56 x 0.085 N

F=698.83 N

a)F=698.83 N

b)K=8221.56 N/m

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3 years ago
Write the ground-state electron configurations of the following ions. (a) Li+ (b) N3− (c) In3+ (Use the noble gas core electron
maria [59]

Li+  [He]

N³-  [Ne]

In³+  [Kr] 4d10

Tl+  [Xe] 4f14 5d10 6S2

6 0
3 years ago
Read 2 more answers
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