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ladessa [460]
4 years ago
5

Which best describes the result when the concentration of a solution is increased? The amount of solute is increased, and the co

nductivity of the solution is increased. The amount of solute is decreased, and the conductivity of the solution is decreased. The amount of solute is increased, and the conductivity of the solution is decreased. The amount of solute is decreased, and the conductivity of the solution is increased.
Physics
1 answer:
oee [108]4 years ago
8 0

The amount of solute is increased, and the conductivity of the solution is increased

Explanation:

The ability of a solution to conduct electricity is conductivity.The more concentrated a solution is the higher the conductivity.This is because the concentration of ions will increase.Increasing solute increases the concentration of a solution thus rising the conductivity.

Learn More

Conductivity of a solution :brainly.com/question/9486572

Keywords : concentration, solution, solute, conductivity

#LearnwithBrainly

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Two point charges lie on the x axis. A charge of + 2.30 pC is at the origin, and a charge of − 4.50 pC is at x=−11.0cm.
Radda [10]

r₁ = distance of point A from charge q₁ = 0.13 m

r₂ = distance of point A from charge q₂ = 0.24 m

r₃ = distance of point A from charge q₃ = 0.13 m

Electric field by charge q₁ at A is given as

E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C     towards right

Electric field by charge q₂ at A is given as

E₂ = k q₂ /r₂² = (9 x 10⁹) (4.50 x 10⁻¹²)/(0.24)² = 0.703 N/C    towards left

Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction

Electric field at A will be zero when

E₁ = E₂ + E₃

1.225 = 0.703 + E₃

E₃ = 0.522 N/C

Electric field by charge "q₃" is given as

E₃ = k q₃ /r₃²

0.522 = (9 x 10⁹) q₃/(0.13)²

q₃ = 0.980 x 10⁻¹² C = 0.980 pC

4 0
4 years ago
For each of the statements below, decide which of the Maxwell equations (forstaticsituations) tells you that the statement is tr
Vladimir79 [104]

Answer:

(a)There are no magnetic monopoles. true

(c) There must be a vector potential. true

(d) Charges create electric fields.2. true

Explanation:

a) there are no magnetic monopoles because magnetic field is created by charges (electrons) and these electrons have dipole field so it is not possible to have magnetic dipoles, more ever Gauss's law always explained that there are not magnetic dipoles. furthermore magnetic monopoles aree caused by magnetic charges and we have electric charges.

c)vector potential is a vector field which serves as a potential for magnetic field so, the magnetic field B by Faraday and Gauss's law is also known as vector potential.

d) electric field is solely generated by charges be it static charges or moving charges if there are no charges it is not possible to have an electric field.

3 0
3 years ago
If an unknown element has a mass of 17 and contains 6 neutrons, how many protons does it have ?
lbvjy [14]

The mass number is the total number of protons and neutrons within an atom and since we know that the unknown element has 6 neutrons, we can simply subtract the number of neutrons from the mass number to get the number of protons.

17 - 6 = 11

There are 11 protons in this unknown element.


Extra:

The number of protons (+) and electrons (-) are equal in a neutral atom so since you know that there are 11 protons you also know that there are 11 electrons. On the periodic table, the element with 11 electrons is Na or Sodium.


Hope this helps! :)

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Answer:

if one bulb burns out the other bulbs will also turn off because they are connected to each other.

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If a transformer has 5000 turns on the primary circuit, 3000 turns on
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The answer is C , you’re welcome
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