Explanation:
Non-metals are the species that are electron deficient and they are able to accept one or more electrons from a donor atom in order to complete their octet.
For example, carbon (C), nitrogen (N), chlorine, (Cl), phosphorus (P) etc are all non-metals.
Metals are the species that contain more number of electrons in their valence shell and in order to attain stability they easily lose an electron.
For example, sodium (Na), lithium (Li), Beryllium (Be), Magnesium (Mg) etc are all metals.
Metalloids are the species that show properties of both metals and non-metals.
For example, Boron (B), Antimony (Sb), Silicon (Si) and Germanium (Ge) etc are metalloids.
Answer:
2KBr + MgF₂ –> 2KF + MgBr₂
The coefficients are: 2, 1, 2, 1
Explanation:
KBr + MgF₂ –> KF + MgBr₂
The above equation can be balance as illustrated below:
KBr + MgF₂ –> KF + MgBr₂
There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:
KBr + MgF₂ –> 2KF + MgBr₂
There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:
2KBr + MgF₂ –> 2KF + MgBr₂
Now, the equation is balanced.
The coefficients are: 2, 1, 2, 1
Answer:
One atom lf helium has a mass of 4 u
Know that 1 u =1.66. 10-24g
Answer:
0.007756M KHP; 0.0009695 moles NaOH reacts; 0.03488M NaOH.
Explanation:
Potassium hydrogen phthalate, KHP, is a salt used as standard to determine concentration of basic solutions as NaOH solutions.
To find molarity of the KHP solution we need to convert mass of KHP to moles and divide this in 125mL = 0.125L:
<em>Moles KHP -Molar mass: 204.22g/mol-:</em>
0.198g * (1mol / 204.22g) = 0.0009695 moles KHP
<em>Molarity:</em>
0.0009695 moles KHP / 0.125L = 0.007756M KHP
NaOH reacts with KHP as follows:
NaOH + KHP → Na⁺ + KP⁻ + H₂O
That means 1 mole of NaOH reacts per mole of KHP, that means moles of NaOH that reacts are = Moles of KHP added:
0.0009695 moles NaOH reacts
In 27.80mL = 0.02780L the NaOH was contained. Molarity is:
0.0009695 moles NaOH / 0.02780L =
0.03488M NaOH
