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Amiraneli [1.4K]
3 years ago
8

According to the model, which two points on Earth are experiencing winter?

Physics
2 answers:
ruslelena [56]3 years ago
6 0

Answer:

The correct answers to ur question are B and D

Explanation:

I know this because I had the same questions on my quiz and I got them right. Also there is another question just like this asking "According to the model, which two points on Earth are experiencing summer?" and the correct answer for that question is A and C!

Hope this helps!

quester [9]3 years ago
3 0
B and D
Because these two points are below equator on sun is shining directly above equator which is experiencing summer
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Advocard [28]

Answer:

Resistivity ρ=1.12 x 10^-4 Ωm

Explanation:

ρ= RA/l, where R is resistance, A is cross sectional area and l is length

A=πr^2

Note Current is given R is proportion to temperature and inversely proportional to Current R=(20+273)/14*10^-2 =2000Ω

⇒ρ=R*πr^2/l all length in metre.

8 0
3 years ago
If you weigh 38 kilograms on your bathroom scale, your weight in space will be ________.
harina [27]

Answer:

Less than 36kilo's

Explanation:

5 0
3 years ago
The electric field between two parallel plates is uniform, with magnitude 628 N/C. A proton is held stationary at the positive p
aliina [53]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Data Given:

Electric Field between two parallel plates = 628 N/C

Separation = 4.22 cm

a) In this part, we are asked to calculate the distance from positive plate at which the electron and proton pass each other.

Solution:

First of all:

Force on proton due to the Electric field between the plates is:

F_{p} = q_{p}E

and, we know that, F = ma

So,

m_{p}a = q_{p}E

a = \frac{q_{p}.E }{m_{p} }      Equation 1

So,

The distance covered by the electron is:

S = ut + 1/2at^{2}

Here, u = 0.

S = 1/2at^{2}

Put equation 1 into the above equation:

S = 1/2 x (\frac{q_{p}.E }{m_{p} }  )t^{2}      Equation 2

So,  

Similarly, the distance covered by electron will be:

(D-S) = 1/2 x (\frac{q_{e}.E }{m_{e} }  )t^{2}    Equation 3

We know that the charge of electron is equal to the charge of proton so,

q_{p} = q_{e} = q

By dividing the equation 2 by equation 3, we get:

\frac{S}{D-S} = \frac{m_{e} }{m_{p} }

Solve the above equation for S,

Sm_{p} = m_{e}D - m_{e}S

So,

S = \frac{m_{e}.D }{(m_{e} + m_{p})  }

Plugging in the values,

As we know the mass of electron is 9.1 x 10^{-31} and the mass of proton is 1.67 x 10^{-27}

S = \frac{9.1 . 10^{-31} . 4.22 }{(9.1 . 10^{-31} + 1.67 . 10^{-27}  }

S = 0.002298 cm (Distance from the positive plate at which the two pass each other)

b) In this part, we to calculate distance for Sodium ion and chloride ion as above.

So,

we already have the equation, we need to put the values in it.

So,

S = \frac{m_{Cl}.D }{(m_{Cl} + m_{Na})  }

As we know the mass of chlorine is 35.5 and of sodium is 23

S = \frac{35.5 . 4.22}{(35.5 + 23)}

S = 2.56 cm

7 0
3 years ago
Why are movie scenes in outer space often unrealistic?
kifflom [539]

Answer:

see explanation

Explanation:

by my calculations, i believe it may be because they have to pretend to be in space.

8 0
2 years ago
Read 2 more answers
Real life example for each gas law
Dvinal [7]
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3 0
3 years ago
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