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SpyIntel [72]
2 years ago
9

His is the geologic process of breaking down rocks into smaller and smaller pieces. There are two main types: chemical and mecha

nical.
A) weathering
B) erosion
C) Deposition
Physics
2 answers:
garik1379 [7]2 years ago
8 0

Answer:

Weathering

Explanation:

The geologic process of breaking down rocks into smaller and smaller units or pieces is known as weathering.

The physical disintegration and chemical decomposition of rocks to form sediments and soils is known as weathering.

The agents of weathering are wind, water and glacier.

  • Chemical weathering entails the decomposition of rocks.
  • Mechanical weathering is the physical disintegration of rocks.

Therefore, weathering breaks down rocks.

Erosion removes the weathered materials.

dimulka [17.4K]2 years ago
4 0

Answer:

Weathering

Explanation:

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The type of wetland u are most likely to find carnivorous plant would be a bog.
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3 years ago
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A circular cylinder has a diameter of 3.0 cm and a mass of 25 g. It floats in water with its long axis perpendicular to the wate
Vilka [71]

Answer:

   f = 5.3 Hz

Explanation:

To solve this problem, let's find the equation that describes the process, using Newton's second law

        ∑ F = ma

where the acceleration is

         a = \frac{d^2 y}{dt^2 }

        B- W = m \frac{d^2 y}{dt^2 }

To solve this problem we create a change in the reference system, we place the zero at the equilibrium point

           B = W

In this frame of reference, the variable y'  when it is oscillating is positive and negative, therefore Newton's equation remains

         B’= m \frac{d^2 y'}{dt^2 }

           

the thrust is given by the Archimedes relation

         B = ρ_liquid g V_liquid

     

the volume is

        V = π r² y'

     

we substitute

          - ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }

          \frac{d^2 y'}{dt^2} + \rho_liquid \ g \ \pi  r^2/m ) y' \ =0

this differential equation has a solution of type

         y = A cos (wt + Ф)

where

         w² = ρ_liquid g π r² /m

angular velocity and frequency are related

         w = 2π f

         

we substitute

          4π² f² = ρ_liquid g π r² / m

          f = \frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \  \pi  r^2 \ g}{m } }

calculate

         f = \frac{1}{2 \pi }  \sqrt{ \frac{ 1000 \ \pi  \ 0.03^2 \ 9.8 }{0.025}  }

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6 0
2 years ago
Jan ran 4 miles north in 28 minutes. What was Jan's average velocity?
fenix001 [56]

Answer:

3.83 m/s

Explanation:

Given that,

Distance covered by Jan, d = 4 miles

1 mile = 1609.34 m

4 miles = 6437.38 m

Time, t = 28 minutes = 1680 s

Jan's average speed,

v = d/t

v=\dfrac{6437.38\ \text{m}}{1680\ \text{s}}\\\\v=3.83\ \text{m/s}

Hence, the average velocity of Jan is 3.83 m/s.

6 0
3 years ago
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 2 sin2(t), y = 2 cos2(
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The distance traveled by the particle at the given time interval is 0.28 m.

<h3>Position of the particle at time, t = 0</h3>

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x(0) = 2 sin2(0) = 0

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x = 2 sin2(t)

y = 2 cos2(t)

x(4) = 2 sin2(4) = 0.28

y(4) = 2 cos2(4) = 2(1) = 1.98

<h3>Distance traveled by the particle at the given time interval</h3>

d = √[(x₄ - x₀)² + (y₄ - y₀)²]

d =  √[(0.28 - 0)² + (1.98 - 2)²]

d = 0.28 m

Thus, the distance traveled by the particle at the given time interval is 0.28 m.

Learn more about distance here: brainly.com/question/23848540

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7 0
1 year ago
For a relative frequency distribution, relative frequency is computed is computed as ____________.
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Answer:

For a relative frequency distribution, relative frequency is computed as the class frequency divided by the number of observations.

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