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Viktor [21]
3 years ago
7

The process by which water vapor changes to liquid water is called

Chemistry
1 answer:
andre [41]3 years ago
6 0
When water is turned into vapor (a gas), that is called evaporation.

Hope this helps. :)
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Select the most likely product for this reaction: upper a g upper n upper o subscript 3 (a q) plus upper n a upper o upper h (a
Mamont248 [21]

One of the most likely products for the reaction would be Ag_2O

<h3>Chemical reactions</h3>

The reaction between AgNO_3 and NaOH yields 3 products which are Ag_2O (a precipitate), NaNO_3, and H_2O as shown by the equation below:

2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

More on precipitation reaction can be found here: brainly.com/question/24158764

#SPJ4

5 0
2 years ago
Read 2 more answers
What are the products in this chemical reaction? 2H3PO4+3Ca(OH)2→Ca3(PO4)2+6H2O
finlep [7]
<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

reactants→products

reactants refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

products refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction,Ca_{3}(PO_{4})_{2},H_{2}O are written on the right side of the equation.

So,Ca_{3}(PO_{4})_{2},H_{2}O are the products.

5 0
2 years ago
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What is a property of a combustion reaction?
ohaa [14]
A, O2 has to be a reactant for combustion to burn
8 0
3 years ago
Which substance can not be decomposed by a chemical change?<br> (1) AlCl3 (3) HI<br> (2) H2O (4) Cu
user100 [1]
Cooper is the substance that can't be decomposed by a chemical chAnge. So 4)
5 0
2 years ago
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What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
2 years ago
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