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Helga [31]
2 years ago
13

Liquid nitrogen is cold and can be used to cool objects to -196°C. If you put the bottle of warm air in liquid nitrogen at this

temperature, what would the volume (mL) of air in the bottle be?
Chemistry
1 answer:
shtirl [24]2 years ago
8 0

Answer:

It will boil.

Literally, every liquid has a boiling point, unless it chemically decomposes before it gets to that point (which liquid nitrogen certainly doesn't). At normal atmospheric pressure, it can be 'heated' to -196 C. At that point, any heat you put into it will go into boiling liquid nitrogen into nitrogen gas. At higher pressures, the same thing will happen at a higher temperature. Once all the liquid is boiled, the gas will continue to rise in temperature as long as heat is being added.

Explanation:

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A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 42 g of water (with an
professor190 [17]

Answer:

1.717 J/g °C  ( third option)

Explanation:

A piece of the unknown metal dropped into water this means that Q of metal is equal to Q of the water. We write this equality as follows:

<u>Step 1: writing the formulas:</u>

Q = mc∆T

⇒ -Q(metal) = Q(water)   Because :Metal dropped into water this means that Q of metal is equal to Q of the water.

<em>We can write the formula different :</em>

Mass of metal * (cmetal)(ΔT) = Mass of water *(cwater) (ΔT)

⇒ Here c is the specific heat and depends on material and phase

<em>For this case :</em>

mass of the metal  = 68.6g

mass of the water = 42g

Specific heat of the metal = TO BE DETERMINED

Specific heat of the water = 4.184J/g °C

Initial temperature of the metal = 100 °C  ⇒ Change of temperature: 52.1 - 100

Initial temperature of the water = 20°C  ⇒ Change of temperature:  52.1 - 20

<u />

<u>Step 2: Calculating specific heat of the metal</u>

-(Mass of metal) * (cmetal)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-68.6g (cmetal)(52.1 - 100) = 42g (4.184j/g °C) (52.1 - 20)

-68.6g *cmetal * (-47.9) = 42g (4.184j/g °C) *(32.1)

3285.94 * cmetal = 5640.87

cmetal = 5640.87 / 3285.94 = 1,71667 J/g °C

cMetal = 1.717 J/g °C

4 0
3 years ago
En el enlace covalente entre azufre y carbono (6 y 4 electrones en su ultima capa respectivamente) la molécula tendrá ?
d1i1m1o1n [39]

Answer:

a- Uno de carbono y dos de azufre

Explanation:

El compuesto formado entre el carbono y el azufre es CS2.

El carbono forma dos enlaces dobles con dos átomos de azufre.

Por lo tanto, el compuesto contiene un átomo de carbono y dos átomos de azufre.

6 0
3 years ago
What is the mass of HF produced by three reaction of 3.0 10 to the 23 molecules of H2 with excess F2
JulijaS [17]

Answer:

It is 20. g HF

Explanation:

H2 + F2 ==> 2HF  ...  balanced equation

Since the question is asking us to find the mass of product formed, we will want to first convert the molecules of H2 into moles of H2 (we could do this at the end of the calculations, but it's just as easy to do it now).

moles of H2 present (using Avogadro's number):  

3.0x1023 molecules H2 x 1 mole H2/6.02x1023 molecules = 0.498 moles H2

From the balanced equation, we see that 1 mole H2 produces 2 moles HF.  Therefore, we can now find the theoretical mass of HF produced from 0.498 moles H2:

0.498 moles H2 x 2 moles HF/1 mol H2 = 0.996 moles HF formed.

The molar mass of HF = 20.01 g/mole, thus...

0.996 moles HF x 20.01 g/mole = 19.93 g HF = 20. g HF formed (to 2 significant figures)

6 0
3 years ago
Why does the reaction proceed more quickly when the surface area is increased?
Gelneren [198K]
When particles collide with the surface of the solid.
3 0
3 years ago
Use the particle theory to describe each of the three states of matter.
Anna007 [38]
Matter can exist in one of three main states: solid, liquid, or gas. Solid matter is composed of tightly packed particles. A solid will retain its shape; the particles are not free to move around. ... Gaseous matter is composed of particles packed so loosely that it has neither a defined shape nor a defined volume.
7 0
3 years ago
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