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Helga [31]
1 year ago
13

Liquid nitrogen is cold and can be used to cool objects to -196°C. If you put the bottle of warm air in liquid nitrogen at this

temperature, what would the volume (mL) of air in the bottle be?
Chemistry
1 answer:
shtirl [24]1 year ago
8 0

Answer:

It will boil.

Literally, every liquid has a boiling point, unless it chemically decomposes before it gets to that point (which liquid nitrogen certainly doesn't). At normal atmospheric pressure, it can be 'heated' to -196 C. At that point, any heat you put into it will go into boiling liquid nitrogen into nitrogen gas. At higher pressures, the same thing will happen at a higher temperature. Once all the liquid is boiled, the gas will continue to rise in temperature as long as heat is being added.

Explanation:

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Which orbital do potassium's outermost electrons occupy? 4s 4p 4d 3s
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Which of the following has the strongest buffering capacity? A. H2O B. 0.1 M HCl C. 0.1 M carbonic/bicarbonate (H2CO3/HCO3-) at
enyata [817]

Explanation:

(A)   As we know that carbonic acid (H_{2}CO_{3}) and Sodium bicarbonate (NaHCO_{3}) forms an acidic buffer.

Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.

               pH = pK_{a} + log(\frac{[Salt]}{[Acid]}) ........... (1)

So mathematically,  if [Salt] = [Acid]  then \frac{[Salt]}{[Acid]} = 1 .

And,  log (\frac{[Salt]}{[Acid]}) = 0

Therefore, equation (1) gives us the following.

         pH = pK_{a} (when acid and salt are equal in concentration)

Hence, pK_{a} of H_{2}CO_{3} (carbonic acid) is 6.35.

And, with this we have following results.

In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].

Hence, for the cases pH = pK_{a} = 6.35.

(B)    [NaHCO_{3}] = 0.045 M and,  [H_{2}CO_{3}] = 0.45 M

Hence,   pH = 6.35 + log([NaHCO_{3}][[H_{2}CO_{3}])

                     = 6.35 + log(\frac{0.045}{0.45})

                     = 6.35 + (-1)

                     = 5.35

Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.

(C)    [NaHCO_{3}] = 0.45 M [H_{2}CO_{3}]

                          = 0.045 M

So,       pH = 6.35 + log(\frac{[NaHCO_{3}]}{[H_{2}CO_{3}]})

                  = 6.35 + log(\frac{0.45}{0.045})

                  = 6.35 + (+1)

                 = 7.35

This means that pH on Basic side makes it no more acidic buffer.

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Which are examples of contact forces?
lesantik [10]

Answer:

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Explanation:

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Contact Forces  are the forces which is requires a contact between two bodies to occur.

The Types of contact forces are given below:

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source: http://chemistry.elmhurst.edu/vchembook/207epgeom.html

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