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tatuchka [14]
2 years ago
5

8. While taking a measurement, Ajay put the 2nd mark of the scale to the edge of the line and the mark that pointed to the end o

f the line was 80 cm. What is the total length of the line? Write the length of line in meter also.
Physics
1 answer:
Leni [432]2 years ago
4 0

Answer:

The length of line is 78 cm or 0.78 m.

Explanation:

initial reading 2 mark

final reading 80 cm

The length of the line

= final reading - initial reading

= 80 - 2

= 78 cm

1 cm = 0.01  m

So, 78 cm = 0.78 m

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An object accelerates to a velocity of 230 m/s over a time of 2.5 s. The acceleration it experienced was 42 m/s2. What was its i
zmey [24]

Answer:

230 = x + 105

x= 125

Explanation:

v = v0 + at

5 0
3 years ago
Continental drift speed is 1x 10^-9 m/s. This is equivalent to a speed of
likoan [24]
<span><em>Continental drift</em> is one of the earliest ways that geologists thought <em>continents</em><span> moved over time. It is believed in this theory that the Earth’s movement of the continents are relative to each other.  This idea was subsumed by the plate tectonics theory. Now, what is the speed of the continental drift?</span></span>  

Continental drift speed is 1x 10^-9 m/s.
This is equivalent to a speed of:
 1 x 10 ^-9 m/s
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6 0
3 years ago
How far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.9 m/s ?
Akimi4 [234]

Answer:19.5 m

Explanation:

Given

coefficient of kinetic Friction \mu _k=0.10

Initial speed u=3.9\ m/s

Friction is present so it tries to stop to the object and stops it completely after moving certain distance let say s

maximum deceleration provided by friction is

a_{max}=\mu _k\cdot g

a_{max}=0.1\times 3.9=0.39\ m/s^2

using equation of motion

v^2-u^2=2 as

where v=final\ velocity

u=initial velocity

a=acceleration

s=displacement

(0)-(3.9)^2=2\times (-0.39)\times s

s=19.5\ m

6 0
3 years ago
Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of lig
PSYCHO15rus [73]
Give me some answer choices and i will be happy to help
4 0
3 years ago
A loop of wire in the shape of a rectangle rotates with a frequency of 284 rotation per minute in an applied magnetic field of m
yaroslaw [1]

Answer:

a) Magnitude of maximum emf induced = 0.0714 V = 71.4 mv

b) Maximum current through the bulb = 0.00793 A = 7.93 mA

Explanation:

a) The induced emf from Faraday's law of electromagnetic induction is related to angular velocity through

E = NABw sin wt

The maximum emf occurs when (sin wt) = 1

Maximum Emf = NABw

N = 1

A = 4 cm² = 0.0004 m²

B = 6 T

w = (284/60) × 2π = 29.75 rad/s

E(max) = 1×0.0004×6×29.75 = 0.0714 V = 71.4 mV

Note that: since we're after only the magnitude of the induced emf, the minus sign that indicates that the induced emf is 8n the direction opposite to the change in magnetic flux, is ignored for this question.

b) Maximum current through the bulb

E(max) = I(max) × R

R = 9 ohms

E(max) = 0.0714 V

I(max) = ?

0.0714 = I(max) × 9

I(max) = (0.0714/9) = 0.00793 A = 7.93 mA

Hope this Helps!!

8 0
3 years ago
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