Answer:
The z-component of the force is 
Explanation:
From the question we are told that
The charge on the particle is 
The magnitude of the magnetic field is 
The velocity of the particle toward the x-direction is 
The velocity of the particle toward the y-direction is
The velocity of the particle toward the z-direction is
Generally the force on this particle is mathematically represented as
So we have
substituting values
 + [(5.58*10^{4}) (0.700)]\r y)](https://tex.z-dn.net/?f=%5C%3D%20F%20%20%3D%20%287.7%20%2A10%5E%7B-8%7D%29%28%5B%20%28-2.61%2A10%5E%7B4%7D%29%20%280.700%29%5D%28-%5Cr%20%20z%29%20%2B%20%5B%285.58%2A10%5E%7B4%7D%29%20%280.700%29%5D%5Cr%20y%29)
So the z-component of the force is
Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).
Answer:
72 volts.
Explanation:
To solve this, we have to use the Ohm's law.
The ohm's law tells us that the voltage drop of a resistor is directly proportional to the current applied to the conductor.
in this case the current is 1.8 amps and the resistor is 40 ohm
so
.
Answer:
a,b,c,d,,f, g, j
Explanation:
e) equipotential lines are lines connecting points of equal potential
h) electric field inside the conductor is non-zero even when there is net movement of charge or non-zero current.
i) capacitors' plates are charged and an electric field exists between the plates.
Answer:
a) P=0.25x10^-7
b) R=B*N2*E
c) N=1.33x10^9 photons
Explanation:
a) the spontaneous emission rate is equal to:
1/tsp=1/3 ms
the stimulated emission rate is equal to:
pst=(N*C*o(v))/V
where
o(v)=((λ^2*A)/(8*π*u^2))g(v)
g(v)=2/(π*deltav)
o(v)=(λ^2)/(4*π*tp*deltav)
Replacing values:
o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2
the probability is equal to:
P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7
b) the rate of decay is equal to:
R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system
c) the number of photons is equal to:
N=(1/tsp)*(V/C*o)
Replacing:
N=100/(3*3x10^10*8.3x10^-19)
N=1.33x10^9 photons
