Ask question

Ask question

All categories

2 years ago

5

A particular lightbulb is designed to consume 40 W when operating on a car's 12-V DC electric power. If you supply that bulb wit

h 12-V AC power from a transformer, how much power will it consume

1 answer:

Andrew [12]2 years ago

4 0

40V because it will provide the same amount of power.

You might be interested in

Density of water 1000kgper m^3 What will be the volume of 3500<br>kg water

skad [1K]

Answer:

<em>The volume of water is 3.5 cubic meter</em>

Explanation:

<u>Density </u>

The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

$\displaystyle \rho=\frac{m}{V}$

We are given the density of water as $\rho=1,000\ kg/m^3$ .It's required to find the volume of m=3,500 kg of water. Solving for V:

$\displaystyle V=\frac{m}{\rho}$

$\displaystyle V=\frac{3,500}{1,000}$

$V=3.5\ m^3$

The volume of water is 3.5 cubic meter

5 0

3 years ago

Sound waves require a ________ to travel through

Karolina [17]

Answer:

sound Requires a medium in order to travel.

7 0

3 years ago

Read 2 more answers

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

brilliants [131]

Answer:

Explanation:

When the craft was stationary , weight will be balanced by tension

T = mg

T = 7000 N

A)

when the craft was being lowered to the seafloor

drag force will act in upper direction , so

T₁ + 1800 = mg

T₁ = mg - 1800

= 7000 - 1800

= 5200 N

52 X 10² N

B)

when the craft was being raised from the seafloor , Tension will act in downward direction

T₂ = mg+ 1800

T₂ = 7000 - 1800

= 8800N

3 0

3 years ago

The fully loaded bus accelerates uniformly from rest to a speed of 14 m / s. The time taken to reach a speed of 14 m / s is 20 s

tino4ka555 [31]

Answer:

0.7m/s^2

Explanation:

acceleration=(final-initial velocity)/time

x=(14-0)/20

x=14/20

x=0.7

3 0

3 years ago

A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

levacccp [35]

Answer:

$7.69533\times 10^{-11}\ m^3/s$

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = $2.5\times 10^{-5}\ m$

$\eta$ = Viscosity of liquid = $2.084\times 10^{-3}\ Pas$

l = Length of artery = $1.1\times 10^{-3}\ m$

From Poiseuille's equation we have

$Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s$

The flow rate of blood is $7.69533\times 10^{-11}\ m^3/s$

8 0

3 years ago