Answer:
Vgr = 0.122 = 12.2 vol %
Explanation:
Density of ferrite = 7.9 g/cm^3
Density of graphite = 2.3 g/cm^3
<u>compute the volume percent of graphite </u>
for a 3.9 wt% cast Iron
W∝ = (100 - 3.9) / ( 100 -0 ) = 0.961
Wgr = ( 3.9 - 0 ) / ( 100 - 0 ) = 0.039
Next convert the weight fraction to volume fraction using the equation attached below
Vgr = 0.122 = 12.2 vol %
Answer:
Power consume by compressor=113,726.87 KW
Explanation:
Given:
Actually compressor is an open system, so here we will use first law of thermodynamics for open system .
We know that first law of thermodynamics for steady flow
We know thatand we take the air as ideal gas.
System is in steady state then mass flow rate in =mass flow rate out
Mass flow rate=
So mass flow rate = ,
=1.23×200×2 Kg/s
=541.17 Kg/s
,
=80.07 m/s
Enthalpy of ideal gas h=
So
Now by putting the values
Here Q=0 because heat transfer is zero here.
W= -210.15 KJ/kg
So power consume by compressor=541.17×210.15
=113,726.87 KW
18.14% of the bags contains less than 22 kg
<h3>What is
z score?</h3>
Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
z = (raw score - mean) / standard deviation
Given that:
Mean = 22.73 kg, standard deviation = 0.80 kg
a) For <22:
z = (22 - 22.73)/0.8 = -0.91
P(z < -0.91) = 0.1814
18.14% of the bags contains less than 22 kg
Find out more on z score at: brainly.com/question/25638875
Answer:
R = 0.5825 k ohm
Explanation:
given data
vD = 0.75 V
iD = 1mA
resistor R = 15-V
solution
we get here first vD that is
vD =
vD = 0.825
so
iD = Ise ×
n = 1
so we can say
so it will
iD2 = iD1 ×
put here value and we get
iD2 = 1 ×
iD2 = 1 ×
iD2 = 20.086 mA
so
R will be
R =
R = 0.5825 k ohm