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faltersainse [42]
3 years ago
10

A redecor travelling of 94 m/s s lows at a anstant

Physics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

638 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 94 m/s

Final velocity (v) = 22 m/s

Time (t) = 11 s

Distance (s) =?

We can obtain the distance travelled by using the following formula:

s = (u + v) t /2

s = (94 + 22) × 11 /2

s = 116 × 11 /2

s = 1276 /2

s = 638 m

Thus, the distance travelled is 638 m.

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You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel
Lerok [7]

Answer: I would say the object with the Lower velocity because Lighter with Higher velocity makes it heavy, velocity is how heavy something is so the lighter it is the less difficult it will be to catch.

7 0
3 years ago
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 146 cm and makes an angl
svetlana [45]

Answer:

B = 191.26 cm

θ = -14.73°

Explanation:

given,

magnitude of the first displacement(A) = 146 cm

at an angle of 124°

resultant magnitude = 137 cm

and angle made with x-axis by the resultant(R) = 32.0°

component of A in X and Y direction

A x = A cos θ  = 146 cos 120° = -73 cm

A y = A sin θ = 146 sin 120° = 126.4 cm

now component of resultant in x and y direction

R x = 137 cos 35°

    = 112.2 cm

R y = 137 sin 35°

     = 78.6 cm

resultant is the sum of two vectors

R = A + B

R x = A x + B x

B x =  112.2 - (-73) = 185.2 cm

B y = R y - A y

B y = 78.6 - 126.4 = -47.8 cm

magnitude of B

B = \sqrt{B_x^2+B_y^2}

B = \sqrt{185.2^2+-47.8^2}

B = 191.26 cm

angle\theta = tan^{-1}\dfrac{-47.8}{185.2}

θ = -14.73°

6 0
4 years ago
Explain how the thermal energy of a swimming pool compares to the thermal energy of a lake at the same temperature.
astra-53 [7]
There is more thermal energy in the lake because there is more water which is more thermal energy
3 0
3 years ago
Calculate the wave number for the infrared absorption of D35Cl when there is a transition from v=0 to v=1 (Unit: cm^-1, 4-digit
AVprozaik [17]

Answer:

wave number = 0.3348 * 10⁻⁸ cm⁻¹

Explanation:

Given data:

K = 4.808 * 10^2 N/m

<u>Determine the wave number for the infrared absorption</u>

considering vibrational Spectre

k' =  2n / λ ---- ( 1 )

λ = c / v ----- ( 2 )

v = √k / u  --- ( 3 )

where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency,  k = force constant, u = reduced mass

u = 1.90415 for  D35Cl

Input equations 2 and 3 into equation 1 to get the final equation

K' = 2n/c * √k / u

   = ( 2 * 3.14 ) / 2.98 * 10^8  ] * (√ 4.808 * 10^2 / 1.90415 )

   = 33.486 * 10⁻⁸ m⁻¹  ≈ 0.3348 * 10⁻⁸ cm⁻¹

6 0
3 years ago
An example of a qualitative observation would be ___________.
bazaltina [42]
All of those! A qualitative observation is any one that doesn't include numbers. <em>Quantitative </em>observations include numbers, but not usually any other kind of information.
4 0
4 years ago
Read 2 more answers
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