The fact that Voyager 10 continues to speed out of the solar system even though its rockets have no fuel, is an example of Newton's first law.
Sir Isaac Newton is a British mathematician, physicist, astronomer, alchemist, theologist, author, one of the greatest mathematicians and physicists of all time, and one of the most influential scientists. Widely recognized as a person. He was a key figure in the philosophical revolution known as the Enlightenment.
Isaac Newton is best known for his discoveries in optics (composition of white light) and mathematics (calculus). His best known is the formulation of the three laws of motion, which are the basic principles of modern physics.
Newton's first law states that a stationary or uniformly moving object remains straight unless its state is changed by the action of an external force.
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Answer:
v = 719.2 m / s and a = 83.33 m / s²
Explanation:
This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is
v - v₀ =
ln (M₀ / M)
where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket
In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s
m_fuel = 75 10
m_fuel = 750 kg
As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is
M = 3000 -750 = 2250 kg
let's calculate
v - 0 = 2500 ln (3000/2250)
v = 719.2 m / s
To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is
Push = v_{e} dM / dt
let's calculate
Push = 2500 75
Push = 187500 N
If we use Newton's second law
F = m a
a = F / m
let's calculate
a = 187500/2250
a = 83.33 m / s²
Answer:
PE = 882 J
Explanation:
Through the International System we know that the gravity of the earth is 9.8 m/s², so...
Data:
- m = 45 kg
- g = 9.8 m/s²
- h = 2 m
- PE = ?
Formula:
Replace and solve:
The potential energy of the sled is <u>882 Joules</u>.
Greetings.
-- "Work" is the product of (force exerted on the object) x (distance the object moves in the direction of the force).
Since the orbit is a circle, the gravitational force toward the center is always perpendicular to the orbit. The object never moves in the direction of the force. If it did, it wouldn't be 'R' away from the center of the circle.
So the product of (gravitational force) x (distance in the direction of the force) is always zero.
-- Even if the orbit ISN't a circle . . . there are some parts of the orbit that aren't quite perpendicular to the gravitational force. If the satellite is traveling through one of those parts AND getting closer to the central body, then gravity is doing positive work on the satellite. If the satellite is traveling through one of those parts and getting FARTHER from the central body, then the satellite is the one doing positive work, and gravity is doing 'negative work'. The work done by gravity ... and the work done by the satellite ... is zero over a complete revolution, although not zero at every point.
This is exactly the definition of a "Conservative Force" ... a force that does zero work through one trip around any CLOSED path. Gravity is a conservative force, and so is the Electrostatic force.