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Y_Kistochka [10]
4 years ago
15

In the reaction below, how would adding more of reactant A affect the equilibrium of the system? (2 points)

Physics
2 answers:
Vera_Pavlovna [14]4 years ago
7 0
A+b=C+D=E that’s your answer
pogonyaev4 years ago
6 0

Answer:

It would also shift left towards the reactions

Explanation:

got it right on my quiz

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A softball needs to hit a bucket 43. 0 m away on flat ground. if it is aimed at 72. 0, what must its inital velocity be?
ddd [48]

Answer:

This can easily be solved using the "range" formula

R = V0^2 * sin 2θ / g

V0^2 = g R / sin 2θ = 9.80 * 43 / sin 144 = 717 m^2/s^2

V0 = 26.8 m/s

3 0
1 year ago
The following quantities describe location or its change:position, distance, and a displacement. Which are vectors?
-Dominant- [34]

As per the question there are three physical quantities named as position,distance and displacement.

Before coming into a conclusion first we have to understand a vector and a scalar.

A scalar quantity is a quantity which has only magnitude for it's complete specifications.

A vector is a quantity which has magnitude as well as direction and at the same time it is in accordance with the paraellogram law of vector addition.

Out of the three options displacement and position are vector quantities.It is because it is the minimum distance between two points .It has magnitude as well as direction.

Distance can not be considered as a vector quantity as it has only magnitude.There is no specific directions of distance travelled.

Position vector is a vector which provides location of an object in a plane or space.It is nothing else except the point which has x,y,z coordinates with origin is taken as the reference point.

Hence position and displacement are vectors

6 0
3 years ago
Read 2 more answers
An artillery shell is launched on a flat, horizontal field at an angle of α = 31.7° with respect to the horizontal and with an i
kompoz [17]

Answer:193.90 m/s

Explanation:

Given

launch angle \theta =31.7^{\circ}

launch velocity v_0=202 m/s

Horizontal velocity of the shell after t=18.96 s

time of flight of Projectile T=\frac{2u\sin \theta }{g}

T={\frac2\times 202\sin 31.7}{9.8}

T=21.66 s

i.e. projectile is declining as t>\frac{T}{2}

but horizontal component of velocity will remain same as there is no opposing force in horizontal direction

Horizontal component of velocity is

u_x=v_0\cos \theta =202\cdot \cos 31.7=193.90 m/s  

8 0
3 years ago
Read 2 more answers
Select the correct answer.
Sergeu [11.5K]
I believe the answer is B: It’s moving at a constant speed.
6 0
3 years ago
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What is dark energy?
olga2289 [7]

Explanation:

Dark Energy. Dark Energy is a hypothetical form of energy that exerts a negative, repulsive pressure, behaving like the opposite of gravity. It has been hypothesised to account for the observational properties of distant type Ia supernovae, which show the universe going through an accelerated period of expansion

6 0
3 years ago
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