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Alisiya [41]
1 year ago
12

a 5.0-ft woman wishes to see a full length image of herself. what is the minimum length mirror required?​

Physics
1 answer:
nadezda [96]1 year ago
4 0

Answer:

2.5 ft

Explanation:

minimum size of the mirror should be one half the person's height.

For this woman of 5 feet height, she would therefore need a mirror of length 2.5 feet

5ft ÷ 2 ft (half) = 2.5ft OR half of 5t is 2.5ft

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Select which geologic events will have an immediate impact on the landscape. Choose three (3).
alexgriva [62]

Answer: A, B, and D,

C is incorrect because continental drift takes several centuries to move the tectonic plates witch is not an immediate impact leaving you with A,B, and D.

6 0
2 years ago
In a controlled experiment why is it important to change just one variable parameter at a time
kiruha [24]
Think of it this way: If you test only one variable then you know that the difference in the experimental and control setup is that one independent variable. If you test more than one you will not know which one made the difference. Hope this helps :)
3 0
3 years ago
A coin is placed 10.8 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly incr
Advocard [28]

Answer:

Coefficient of static friction = 0.547

Explanation:

The maximum resistive force offered by the body(coin)against the applied force(turntable) to continue its state of motion is called Coefficient Of Static Friction

When given

The angular velocity which is 51.1rpm

We are going to calculate velocity of coin

= r*w(angular velocity) = 0.108*(51.1*2π/60) = 0.58

Coefficient=F/N

F= coefficient* N = coefficient*m*g

F= mv^2/r which is centripetal force

Therefore, mv^2/r = coefficient*m*g

coefficient = mv^2/mgr = v^2/rg

Where g,gravity = 9.81

Substitute into the equation coefficient = 0.58^2/9.81*0.108

= 0.547

7 0
3 years ago
When the same force id applied to a smaller area, the pressure is A. Lower B.greater C. Reduced D. The same
irakobra [83]
I believe the correct answer is "B. Greater".
7 0
3 years ago
A 325 g iron bucket contains 527 g of water, both at 21.6°C. A 855 g piece of hot steel (T = 352 degrees Celsius) is added to bu
Neporo4naja [7]

Answer:

T = 18.63 ^oC

Explanation:

As we know that heat given by the hot piece of iron = heat absorbed by water + ice

As we know that

c_{iron} = 0.450 J/g ^oC

also we have

c_{ice} = 2050 J/kg ^oC

now we have

325(0.450)(T-21.6) + 0.527(4186)(T - 21.6) + 0.295(2050)(0 + 22.2) + (0.295)(335000) + 0.295(4186)(T - 0) = 855(0.450)(352 - T)

146.25T - 3159 + 2206T - 47650 + 13425.45 + 98825 + 1234.87T = 135432 - 384.75 T

3971.87 T = 73990.55

T = 18.63 ^oC

3 0
2 years ago
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