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vo = 25 m/sec
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
Answer:
66.8°C
Explanation:
dQ = m*cp*dT where:
m = mass of block
cp = specific heat of iron
dT = temperature change
-------
dQ = 3.5 10^4 J
cp = 0.45 Kj / Kg = 450 J / Kg
3.5 10^4 = 2.3 * 450 * dt-----dt = 35000 / 450 * 2.3 = 33.8 °
-------
Final temperature = 33 + 33.8 = 66.8 °C
Answer: E = 39.54 N/C
Explanation: Electric field can be determined using surface charge density:
where:
σ is surface charge density
is permitivitty of free space (
)
Calculating resulting electric field:
![E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%5B0.3-%28-0.4%29%5D.10%5E%7B-9%7D%7D%7B2.8.85.10%5E%7B-12%7D%7D)
E = 39.54
The resulting Electric Field at any point is 39.54N/C.
Answer:
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