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andrew11 [14]
3 years ago
12

EFGH is an isosceles trapezoid. If EH=4x-27 and FG=x+9, find the value of x. PLEASE HELP ASAP!

Mathematics
1 answer:
djyliett [7]3 years ago
5 0

Answer:

If EFGH is an isosceles trapezoid,

if

EH=4x-27+

FG=x%2B9+

EG=3y%2B19

FH=11y-21

then EH=FG and EG=FH

set up equations:

4x-27=x%2B9 .......solve for x

4x-x=27%2B9

3x=36

x=36%2F3

3y%2B19=11y-21.......solve for y

11%2B19=11y-3y

30=8y

y=30%2F8

y=15%2F4

y=3.75

so,x=12    and y=3.75

you can also check the length of equal sides and equal diagonals:

EH=4%2A12-27+=21

FG=12%2B9+=21

EG=3%283.75%29%2B19=30.25

FH=11%283.75%29-21=30.25x=12

Step-by-step explanation:

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rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
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Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

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the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

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<em>   </em>

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