Answer:
Voltage across element X is 49.26 volts
Explanation:
The kirchhoff's voltage law states that the algebraic sum of voltages around a closed loop is equal to zero.
Applying the kirchhoff's voltage law in loop yields,
-160 + V₁ + V₂ + V₃ + Vₓ + 60 + V₄ = 0
-160 + 60 + V₁ + V₂ + V₃ + Vₓ + V₄ = 0
But we know that V = IR
-100 + IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 0
IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 100
I(R₁ + R₂ + R₃ + Rₓ + R₄) = 100
I = 100/(R₁ + R₂ + R₃ + Rₓ + R₄)
Substitute the given resistor values
I = 100/(18k + 20k + 45k + 100k + 20k)
I = 100/203k
I = 100/203×10³
I = 0.0004926 A
The voltage drop at element x is
Vₓ = IRₓ
Vₓ = 0.0004926*100×10³
Vₓ = 49.26 V
