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Setler [38]
3 years ago
11

How to solve this question

Engineering
1 answer:
Harrizon [31]3 years ago
3 0

Answer:

Voltage across element X is 49.26 volts

Explanation:

The kirchhoff's voltage law states that the algebraic sum of voltages around a closed loop is equal to zero.

Applying the kirchhoff's voltage law in loop yields,

-160 + V₁ + V₂ + V₃ + Vₓ + 60 + V₄ = 0

-160 + 60 + V₁ + V₂ + V₃ + Vₓ + V₄ = 0

But we know that V = IR

-100 + IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 0

IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 100

I(R₁ + R₂ + R₃ + Rₓ + R₄) = 100

I = 100/(R₁ + R₂ + R₃ + Rₓ + R₄)

Substitute the given resistor values

I = 100/(18k + 20k + 45k + 100k + 20k)

I = 100/203k

I = 100/203×10³

I = 0.0004926 A

The voltage drop at element x is

Vₓ = IRₓ

Vₓ = 0.0004926*100×10³

Vₓ = 49.26 V

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Explanation:

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Gas is kept in a 0.1 m diameter cylinder under the weight of a 100 kg piston that is held down by a spring with a stiffness k =
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The spring is compressed by 0.275 meters.

Explanation:

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A horizontal curve of a two-lane undivided highway (12-foot lanes) has a radius of 678 feet to the center line of the roadway. A
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Answer:

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30 = 678 ( 1 - cos (28.655 *s / 678 ) )

( 1 - cos (28.655 *s / 678 ) )  = 30 / 678 = 0.044

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