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3 years ago

How is this technique is adapted to coat continuous steel strip for manufacture of tinplate products?

Engineering

1 answer:

sp2606 [1]3 years ago

3 0

Answer:

Alloying (co -depositing)

Explanation:

Coating:

Coasting is a process to protect the metal from corrosion and other defects. Due to presence of moisture in the atmosphere one layer of oxide form on the surface of metal and due to this metal loos it strength.

Steel is coated by tin to prevent the steel from rust . Alloying is the best method for tin coating .Generally alloys like tin lead,tin copper etc.

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Ierofanga [76]

The length of the arm is the main part of natur

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2 years ago

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Create a C language program that can be used to construct any arbitrary Deterministic Finite Automaton corresponding to the FDA

otez555 [7]

Answer:

see the explanation

Explanation:

/* C Program to construct Deterministic Finite Automaton */

#include <stdio.h>

#include <DFA.h>

#include <stdlib.h>

#include <math.h>

#include <string.h>

#include <stdbool.h>

struct node{

struct node *initialStateID0;

struct node *presentStateID1;

};

printf("Please enter the total number of states:");

scanf("%d",&count);

//To create the Deterministic Finite Automata

DFA* create_dfa DFA(){

q=(struct node *)malloc(sizeof(struct node)*count);

dfa->initialStateID = -1;

dfa->presentStateID = -1;

dfa->totalNumOfStates = 0;

return dfa;

}

//To make the next transition

void NextTransition(DFA* dfa, char c)

{

int tID;

for (tID = 0; tID < pPresentState->numOfTransitions; tID++){

if (pPresentState->transitions[tID].condition(c))

{

dfa->presentStateID = pPresentState->transitions[tID].toStateID;

return;

}

dfa->presentStateID = pPresentState->defaultToStateID;

}

//To Add the state to DFA by using number of states

void State_add (DFA* pDFA, DFAState* newState)

{

newState->ID = pDFA->numOfStates;

pDFA->states[pDFA->numOfStates] = newState;

pDFA->numOfStates++;

}

void transition_Add (DFA* dfa, int fromStateID, int(*condition)(char), int toStateID)

{

DFAState* state = dfa->states[fromStateID];

state->transitions[state->numOfTransitions].toStateID = toStateID;

state->numOfTransitions++;

}

void reset(DFA* dfa)

{

dfa->presentStateID = dfa->initialStateID;

}

5 0

3 years ago

Determine the magnitude of the resultant force and the moment about the origin. Note: the symbol near the 140 N-m moment are not

arlik [135]

Answer:

R = 148.346 N

M₀ = - 237.2792 N-m

Explanation:

Point O is selected as a convenient reference point for the force-couple system which is to represent the given system

We can apply

∑Fx = Rx = - 60N*Cos 45° + 40N + 80*Cos 30° = 66.8556 N

∑Fy = Ry = 60N*Sin 45° + 50N + 80*Sin 30° = 132.4264 N

Then

R = √(Rx²+Ry²) ⇒ R = √((66.8556 N)²+(132.4264 N)²)

⇒ R = 148.346 N

Now, we obtain the moment about the origin as follows

M₀ = (0 m*40 N)-(7 m*60 N*Sin 45°)+(4 m*60 N*Cos 45°)-(5 m*50 N)+ 140 N-m + (0 m*80 N*Cos 30°) + (0 m*80 N*Sin 30°) = - 237.2792 N-m (clockwise)

We can see the pic shown in order to understand the question.

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3 years ago

What is kirchoff's current law?

Anastaziya [24]

Answer:

The sum of all currents entering a junction is 0

Explanation:

Current cannot disappear, so the currents leaving a junction have to equal the currents entering a junction. If you would give the currents leaving the junction an opposite sign (e.g., negative) it implies that the sum of all these currents is exactly 0.