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loris [4]
3 years ago
11

How is this technique is adapted to coat continuous steel strip for manufacture of tinplate products?

Engineering
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

Alloying (co -depositing)

Explanation:

Coating:

 Coasting is a process to protect the metal from corrosion and other defects. Due to presence of moisture in the atmosphere one layer of oxide form on the surface of metal and due to this metal loos it strength.

Steel is coated by tin to prevent the steel from rust . Alloying is the best method for tin coating .Generally alloys like tin lead,tin copper etc.

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A force is a push or pull in? A.a circle B.an arc C.a straight line
Salsk061 [2.6K]

Answer:

I think it is B: an arc

Explanation:

Hope this helps. Mark as brainiest

8 0
3 years ago
A cantilever beam AB of length L has fixed support at A and spring support at B.
atroni [7]

The force in the spring will be F =\dfrac{KPl^3}{3EI}.

The deflection of the beam will be \rho = 0.15(\dfrac{KPL^3}{3EI})

<h3>What is a cantilever beam?</h3>

A rigid, horizontally extending structural member known as a cantilever is supported at only one end. Typically, it extends from a solidly affixed flat vertical surface, such as a wall.

Given that:-

  • A cantilever beam AB of length L has fixed support at A and spring support at B.
  • The spring behaves in a linearly elastic manner with stiffness k. If a concentrated load P is applied at B.

The spring force will be calculated as:-

F = kx

Deflection will be given by:-

x = \dfrac{PL^3}{3EI}

The spring force will be calculated by:-

F = \dfrac{KPL^3}{3EI}

The deflection of the beam will be given as:-

\rho = \dfrac{0.15KPL^3}{3EI}

Therefore the force in the spring will be F =\dfrac{KPl^3}{3EI}..The deflection of the beam will be \rho = 0.15(\dfrac{KPL^3}{3EI})

To know more about Cantilever beam follow

brainly.com/question/16791806

#SPJ1

7 0
2 years ago
If 100 J of heat is added to a system so that the final temperature of the system is 400 K, what is the change in entropy of the
Vitek1552 [10]

Answer:

0.25 J/K

Explanation:

Given data in given question

heat (Q) = 100 J

temperature (T) = 400 K

to find out

the change in entropy of the given system

Solution

we use the entropy change equation here i.e  

ΔS = ΔQ / T           ...................a

Now we put the value of heat (Q) and Temperature (T) in equation a

ΔS is the entropy change, Q is heat and T is the temperature,  

so that

ΔS = 100/400 J/K

ΔS = 0.25 J/K

4 0
3 years ago
About what thickness of aluminum is needed to stop a beam of (a) 2.5-MeV electrons, (b) 2.5-MeV protons, and (c) 10-MeV alpha pa
Nana76 [90]

The thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

<h3>Thickness of the aluminum</h3>

The thickness of the aluminum can be determined using from distance of closest approach of the particle.

K.E = \frac{2KZe^2}{r}

where;

  • Z is the atomic number of aluminium  = 13
  • e is charge
  • r is distance of closest approach = thickness of aluminium
  • k is Coulomb's constant = 9 x 10⁹ Nm²/C²
<h3>For 2.5 MeV electrons</h3>

r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (1.6\times 10^{-19})^2}{2.5 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m

<h3>For 2.5 MeV protons</h3>

Since the magnitude of charge of electron and proton is the same, at equal kinetic energy, the thickness will be same. r = 1.5 x 10⁻¹⁴ m.

<h3>For 10 MeV alpha-particles</h3>

Charge of alpah particle = 2e

r = \frac{2KZe^2}{K.E} \\\\r = \frac{2 \times 9\times 10^9 \times 13\times (2 \times 1.6\times 10^{-19})^2}{10 \times 10^6 \times 1.6 \times 10^{-19}} \\\\r = 1.5 \times 10^{-14} \ m

Thus, the thickness of aluminium needed to stop the beam electrons, protons and alpha particles at the given dfferent kinetic energies is 1.5 x 10⁻¹⁴ m.

Learn more about closest distance of approach here: brainly.com/question/6426420

7 0
2 years ago
Vital role of maritime english among seaferers
seropon [69]

Answer:

uehgeg7djw7heidiisosowiuisiejei2k

8 0
3 years ago
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