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loris [4]
3 years ago
11

How is this technique is adapted to coat continuous steel strip for manufacture of tinplate products?

Engineering
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

Alloying (co -depositing)

Explanation:

Coating:

 Coasting is a process to protect the metal from corrosion and other defects. Due to presence of moisture in the atmosphere one layer of oxide form on the surface of metal and due to this metal loos it strength.

Steel is coated by tin to prevent the steel from rust . Alloying is the best method for tin coating .Generally alloys like tin lead,tin copper etc.

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What are the two main what are the two main concerns in the research of fluid power efficiency?
Galina-37 [17]

Answer:

The correct option is;

Materials and Components

Explanation:

The efficiency of fluid power is influenced by the components and the materials used to deliver the power of the fluid as such fluid power control are focused on

1) Advances in fluid power

2) Making use of the advantages

3) Making use of the other externally available technological advantages

4) Giving allowance for disadvantages

Areas of interest in advances in fluid power are;

a. Computer optimized flow

b. The use of new and improved materials/coatings

c. The use of components that save energy, such as intelligent supply pressure adapting systems

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2 years ago
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True power can only be measured across what?
loris [4]

Answer: mets

Explanation: meets are good

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3 years ago
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I'm so confused to this question <br>What is the difference between Science and Engineering? ​
muminat

Explanation:

Science is the body of knowledge that explores the physical and natural world. Engineering is the application of knowledge in order to design, build and maintain a product or a process that solves a problem and fulfills a need (i.e. a technology).

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3 years ago
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1) (35 pts) For the curved lifting bar, calculate the stresses at A, B, and the centroid of the section.
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I know the Answer but first you should add me as Brainliest and I Will edit this to Answer.

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2 years ago
A certain part of the cast iron piping of a water distribution system involves a parallel section. Both parallel pipes have a di
Bezzdna [24]

Answer :

<h3>Flow rate in pipe B is = 0.3094 \frac{m^{3} }{s}</h3>

Explanation:

Given :

Length of pipe A L_{A}  = 1500 m

Length of pipe B L_{B} = 2500 m

Flow rate through pipe A Q_{A}  = 0.4 \frac{m^{3} }{s}

Diameter of pipe D = 30 \times 10^{-2} m

Velocity from pipe A,

  V _{A} = \frac{Q_{A} }{A}

  V _{A} = \frac{0.4 \times 4 }{\pi ( 30 \times 10^{-2} )^{2}  }

  V_{A}  = 5.66 \frac{m}{s}

Here, head loss is same because height is same.

    h_{a} = h_{b}

L_{A} V_{A} ^{2} = L_{B}  V_{B} ^{2}

V_{B} = \sqrt{\frac{1500}{2500}}    (5.66)

V_{B} = 4.38 \frac{m}{s}

Now rate of flow from pipe B is,

Q_{B}  = V_{B} A

Q_{B}  = \frac{\pi }{4}  (0.3)^{2} \times 4.38

Q_{B} = 0.3094 \frac{m^{3} }{s}

4 0
3 years ago
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