The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.
<h3>How to calculate probability?</h3>
The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:
= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]
= 42/220 + 18/66
= 0.1909 + 0.2727
= 0.4179
In conclusion, the probability is 0.4179.
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You divide the top number by the bottom number then divide that number by another one. you can also find the greatest common factor and make the denominators equal then divide the fraction and then turn it into a decimal
Simplifying
f(x) = x2 + 8x + -3
Multiply f * x
fx = x2 + 8x + -3
Reorder the terms:
fx = -3 + 8x + x2
Solving
fx = -3 + 8x + x2
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Divide each side by 'x'.
f = -3x-1 + 8 + x
Simplifying
f = -3x-1 + 8 + x
Reorder the terms:
f = 8 + -3x-1 + x
18 inches would be the answer