Answer:
A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68
Step-by-step explanation:
Consider the provided information.
A random sample of 21 checking accounts at the bank are chosen,
That means n=21
df = n-1
df = 21-1=20
We need to Construct and interpret a 95% confidence interval.
Determine t critical value for 95% confidence interval.
0.95=1-α
α=0.05
The sample size is small and it is a two tailed test.
From the t value table confidence interval is 2.086
An average daily balance is $303 and a standard deviation of $63.
Substitute the respective values.
A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68
Answer:
the answer is A and C
Step-by-step explanation:
Let x be the total number of students.
The total of red + blue = x/4 + x/8
The remaining will be : x - x/4 -x/8
But we know the green at 3/5 of the remaining, so the green = 3/5(x - x/4 -x/8)
We also know that 3/5(x - x/4 -x/8) = 15
Solve this equation: and you will find x = 40 (number of students)
Answer:
Step-by-step explanation:
hello :
D: (x + 9)2 + (y + 4)2 = 5
Answer:
The probability that all 4 units are good is 10.66%.
Step-by-step explanation:
Given that a shipement of 14 microwave ovens contains six defective units, and a vending company has ordered 4 of these units and selection will be random, to determine what is the probability that all 4 units are good the following calculation must be performed:
14 - 6 = 8
8/14 x 8/14 x 8/14 x 8/14 = X
0.5714 x 0.5714 x 0.5714 x 0.5714 = X
0.1066 = X
0.1066 x 100 = 10.66
Therefore, the probability that all 4 units are good is 10.66%.
