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3 years ago

What is the weight of a 500g ball? (gravity is 9.8 m/s)

Physics

1 answer:

vovangra [49]3 years ago

7 0

Answer:

4,900

Explanation:

you find the weight by multiplying the ball in grams to the gravity

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A tiger leaps with an initial velocity of 35.0 km/hr at an angle of 13.0ᶿ with respect to the horizontal. What are the component

Lorico [155]

Answer:

Vx = 35 x cos(13deg)

Vy = 35 x sin(13deg) - gt

(g is acceleration due to gravity =~9.8 meter/second^2, t is time in second)

Explanation:

The tiger leaps up, then x and y component of its velocity are:

Vx = Vo x cos(alpha)

Vy = Vo x sin(alpha) - gt

(Vo is tiger's initial velocity, alpha is angle between its leaping direction and horizontal plane)

Hope this helps!

3 0

3 years ago

Helpp pls

Kipish [7]

Answer:

The intensity of the electric field is

$|E|=10654.37 \:N/C$

Explanation:

The electric field equation is given by:

$|E|=k\frac{q}{d^{2}}$

Where:

k is the Coulomb constant
q is the charge at 0.4100 m from the balloon
d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

$|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}$

$|E|=10654.37 \:N/C$

I hope it helps you!

5 0

3 years ago

A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During

Lina20 [59]

Answer:

Magnitude of induced emf is 0.00635 V

Explanation:

Radius of circular loop r = 45 mm = 0.045 m

Area of circular loop $A=\pi r^2$

$A=3.14\times 0.045^2=0.00635m^2$

Magnetic field is increases from 250 mT to 350 mT

Therefore change in magnetic field $dB=250-350=100mT$

Emf induced is given by

$e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}$

$e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V$

Magnitude of induced emf is equal to 0.00635 V

7 0

3 years ago

An electron is released from rest in a weak electric field given by vector E = -1.30 10-10 N/C Äµ. After the electron has travel

Murljashka [212]

Answer:

v = 6.45 10⁻³ m / s

Explanation:

Electric force is

F = q E

Where q is the charge and E is the electric field

Let's use Newton's second law to find acceleration

F- W = m a

a = F / m - g

a = q / m E g

Let's calculate

a = -1.6 10⁻¹⁹ / 9.1 10⁻³¹ (-1.30 10⁻¹⁰) - 9.8

a = 0.228 10² -9.8

a= 13.0 m / s²

Now we can use kinematics, knowing that the resting parts electrons

v² = v₀² + 2 a y

v =√ (0 + 2 13.0 1.6 10⁻⁶)

v = 6.45 10⁻³ m / s

4 0

3 years ago

The department of insurance and safety is led by what official

lawyer [7]

Answer: Georgia Department of Insurance

Explanation: I hope this help :]

6 0

3 years ago

What is the weight of a 500g ball? (gravity is 9.8 m/s)​

What is the weight of a 500g ball? (gravity is 9.8 m/s)