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Andrews [41]
3 years ago
15

What is the weight of a 500g ball? (gravity is 9.8 m/s)​

Physics
1 answer:
vovangra [49]3 years ago
7 0

Answer:

4,900

Explanation:

you find the weight by multiplying the ball in grams to the gravity

You might be interested in
Should we focus on the p-value instead of the alpha level?
madreJ [45]

Answer:

Yes, we must focus on p-value along with the alpha level

Explanation:

Alpha and P values are provides two different set of information. While on one hand alpha values sets an extreme value set before rejecting the hypothesis, P value determines the extremeness of the values in the data set.  Thus, if p values is lesser than or equal to alpha value, the null hypothesis is rejected,  If p value is greater than alpha value, then the null hypothesis is not rejected.  

3 0
3 years ago
A tennis ball with a speed of 11.3 m/s is moving perpendicular to a wall. after striking the wall, the ball rebounds in the oppo
Arlecino [84]

To calculate the average acceleration of the ball we use the formula,

a= \frac{v_{f} -v_{i}}{t}

Here, v_{f} is the final velocity of the ball and v_{i} is the initial velocity of the ball t is the time in contact with the wall.

Given v_{i} = 11.3 m/s towards the wall and v_{f} = 7.2207 m/s

away from the wall and t=0.00803 s.

Substituting these values in above formula , we get

a=\frac{(-7.2207 m/s)-11.3 m/s}{0.00803 s}

Herev_{f} is negative because ball is moving away from the wall.

a= - 2306 .4 \ m/s^{2}

Therefore, average acceleration of the ball is - 2306 .4 \ m/s^{2} (away from the wall).

 

4 0
4 years ago
a projectile is launched straight up at 141 m/s . How fast is it moving at the top of its trajectory? suppose it is launched upw
BARSIC [14]

The velocity of projectile has 2 components, horizontal component vcosθ and vertical component vsinθ, where v is the velocity of projection and θ is the angle between +ve X-axis and projectile motion.

In case 1, θ = 90⁰

    So horizontal component is vcos90 = 0

         Vertical component at maximum height = 0

So velocity at maximum height = 0 m/s


In case 2, θ = 45⁰

    So horizontal component is 141cos45 = 100m/s

         Vertical component at maximum height = 0

So velocity at maximum height = 100 m/s


7 0
3 years ago
Scientists are studying a group of living cells under a microscope. They write down notes about the size, shape, and color of th
Lilit [14]

Answer:

D

Explanation:

descriptive, because scientists are writing down the observations but not making comparisons.  

3 0
3 years ago
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
CaHeK987 [17]

The speed of tsunami is a.0.32 km. 

Steps involved  :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

#SPJ4

6 0
2 years ago
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