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ivann1987 [24]
3 years ago
7

5 examples of neutons 3rd law of motion​

Physics
2 answers:
olga55 [171]3 years ago
6 0

1).  When you push on the wall with your hand, the wall pushes on your hand with an equal force.

2).  You stand on the ground, and the ground pushes up on you with equal force.

3).  When you bat the ball, the ball exerts an equal force on the bat.

4).  When the horse pulls the wagon with 500 pounds of force, the wagon pulls the horse with 500 pounds of force.  The source of that force is the horse, of course.  

5).  When the Earth's gravity pulls on you, the force is called "your weight on Earth".  At the same time, your gravity pulls on the Earth, and that force should be called "the Earth's weight on you".  The forces are equal !  If you weigh 75 pounds on Earth, then the Earth weighs 75 pounds on you.

And by the way, Sir Isaac spelled his name like "Newton".

Lemur [1.5K]3 years ago
3 0

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

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A uniformly charged conducting sphere of 1.3 m diameter has a surface charge density of 8.1 µc/m2. (a) find the net charge on th
8_murik_8 [283]
<span>The surface charge density = q/A So q = surface charge density x Area The surface area of a sphere of radius R is 4*Pi*R^2. R = d/2 where d is diameter. This leaves us with 1.3/2 = 0.65. Area = 4 * pie * (0.65)^2 = 5.30998. So the net charge q = 8.1 * 10^(-6) * 5.30998 = 42.47998 * 10^(-6) The Total electric flux = Q/e_0 where , 8.854 Ă— 10â’12, e_0 is permitivity of free space. So Flux = 42.47998 * 10^(-6) / 8.854 * 10(â’12) = 4.833 * 10^(-6 - (-12)) = 4.833 * 10^(6)</span>
8 0
3 years ago
A cyclist bikes in a straight line at an average velocity of 22 miles/hour east and I’m finishing a 100 mile race how much time
Svet_ta [14]

Answer:

Below

Explanation:

To calculate the time it took for the cyclist to finish their race, you can you this equation :

     time = displacement / velocity

Plug in your values....

     time = (100 mi) / (22 mi/h)

             = 4.54545454.... hours

As for sig figs in this question you would need to round this answer to 1 sig fig because 100 only has 1 sig fig. (you round to the lowest # of sig figs in the question)

     = 5 hours

It took the cyclist 5 hours to complete their race

Hope this helps! Best of luck <3

4 0
3 years ago
It is possible a tree could fall down, even if no one did anything to it. A. True B. False
hichkok12 [17]

Answer:

This is TRUE

Explanation:

The tree can fall down even though no one did anything to it...

A hard breeze can blow and it can fall down or something else can cause it to topple...

Not only humans can make trees topple over...

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

<em>Bonne journée</em><em> </em><em>;</em><em>)</em><em> </em>

8 0
3 years ago
You might say that this experiment was an attempt to build a scale, and then calibrate it against a scale that we trust (the ele
Allushta [10]

No.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.

<h3>What is a random error?</h3>

Random error is defined as the deviation of the total error from its mean value due to chance.

Random errors can result from the instrument not being precise or from mistakes by the researcher.

Random errors can be minimized by taking multiple readings and averaging the results.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.

Learn more about random errors at: brainly.com/question/22041172

3 0
3 years ago
Read 2 more answers
Learning Goal: To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circ
andreev551 [17]

Answer:

v = 15.8 m/s

Explanation:

Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement.  So the variation of mechanical energy is equal to the work of the fictional force

    W_{fr} = ΔEm = Em_{f} -Em₀

Let's write the mechanical energy at each point

Initial

    Em₀ = Ke = ½ k x²

Final

   Em_{f} = K + U = ½ m v² + mg y

Let's use Hooke's law to find compression

    F = - k x

    x = -F / k

    x = 4400/1100

    x = - 4 m

Let's write the energy equation

    fr d = ½ m v² + mgy - ½ k x²

Let's clear the speed

   v² = (fr d + ½ kx² - mg y) 2 / m

   v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50)   2/60.0

   v² = (160 + 8800 - 1470) / 30

   v = √ (229.66)

   v = 15.8 m/s

5 0
4 years ago
Read 2 more answers
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