If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem
1 answer:
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Answer:
Height of mirror 0.075 m
width of mirror 0.325 m
Explanation:
given data
wide = 1.3 m
high = 0.30 m
driver’s eyes = 0.50 m
rear window = 1.50 m
solution
we take here height / width of the mirror is
height / width = .................1
and
height /width of the window is
height /width = .................2
and
distance of eye / window by the mirror is
distance of eye / window = .................3
so here
θ = θi = θr ....................4
and tanθ for vertical is
tanθ =
tanθ = ....................5
so
h = ....................6
put here value and we get
h = 0.075 m
and
when we take here tanθ for horizontal than it will be
tanθ =
tanθ = .......................7
so
....................8
put here value and we get
w = 0.325 m
A charged particle moving in a magnetic field experiences a force equal to:
Thus, the magnitude of the force that the proton experiences is given by:
The magnetic field is perpendicular to the proton's velocity, therefore, we have . Replacing the given values, we obtain: