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tatiyna
2 years ago
5

A floating ice block is pushed through a displacement along a straight embankment by rushing water, which exerts a force on the

block. How much work does the force do on the block during the displacement
Physics
1 answer:
lions [1.4K]2 years ago
8 0

The question is incomplete. Here is the complete question.

A floating ice block is pushed through a displacement vector d = (15m)i - (12m)j along a straight embankment by rushing water, which exerts a force vector F = (210N)i - (150N)j on the block. How much work does the force do on the block during displacement?

Answer: W = 4950J

Explanation: <u>Work</u> (W), in physics, is done when a force acts on an object that has a displacement form a place to another:

W = F · d

As the formula shows, Work is a scalar product, i.e, it results in a number, so, Work only has magnitude.

Force and displacement for the ice block are in 2 dimensions, then work will be:

W = (210)i - (150)j · (15)i - (12)j

W = (210*15) + (150*12)

W = 3150 + 1800

W = 4950J

During the displacement, the ice block has a work of 4950J

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To start with calculating the electric field as a result of the square plate; we use the formula;

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E = \dfrac{8 \times 10^{-6} }{2 \times  8.85 \times 10^{-12}}

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\mathbf{v = 8.035 \times 10^3 \ m/s}

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