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tatiyna
3 years ago
5

A floating ice block is pushed through a displacement along a straight embankment by rushing water, which exerts a force on the

block. How much work does the force do on the block during the displacement
Physics
1 answer:
lions [1.4K]3 years ago
8 0

The question is incomplete. Here is the complete question.

A floating ice block is pushed through a displacement vector d = (15m)i - (12m)j along a straight embankment by rushing water, which exerts a force vector F = (210N)i - (150N)j on the block. How much work does the force do on the block during displacement?

Answer: W = 4950J

Explanation: <u>Work</u> (W), in physics, is done when a force acts on an object that has a displacement form a place to another:

W = F · d

As the formula shows, Work is a scalar product, i.e, it results in a number, so, Work only has magnitude.

Force and displacement for the ice block are in 2 dimensions, then work will be:

W = (210)i - (150)j · (15)i - (12)j

W = (210*15) + (150*12)

W = 3150 + 1800

W = 4950J

During the displacement, the ice block has a work of 4950J

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a transmission-line cable, of length 3 km, consists of 19 strands of identical copper conductors, each 1.5 mm in diameter. becau
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the resistance of the cable is 582.9 ohms

we are given the length of the cable which is  3 km,  of  1.5 mm in, the diameter  and resistivity of copper which is 1.72 m

The formula  we are referring to for calculating the resistance of the  cable is

R = ρl/A.

As there are 19 strands of copper conductors, so the resistance will be

R = 19( ρl/A)

Here  ρ is the resisitivity =  1.72 , l is the length  = 3(1+0.05)*10³3= 3150 m

A=pie/4(1.5 x 10⁻³)^2 =1.766 x 10⁻⁶ =1.766 x 10^-6

Substituting the values in the formula  we  get

R = 19 ( 1.72*3150 )/1.766 x 10⁻⁶

 = 582.9 ohm

To know more about resistance refer to the linkhttps://brainly.com/question/14547003?referrer=searchResults.

#SPJ4

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