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2 years ago

How does the movement of particles of matter change when matter goes from solid to liquid? (1 point)

Physics

1 answer:

Y_Kistochka [10]2 years ago

3 0

Answer: c

Explanation: because if it increases then it gets hotter

if it decreases then its getting colder.

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The three main types of nuclear radiation are alpha, beta, and gamma

valkas [14]

Answer:

Gamma beta alpha

Explanation:

6 0

2 years ago

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Please help I'm stuck on this question

Afina-wow [57]

Answer:

increase

decrease

Explanation:

using formula

Vt=mg/6πηr

so if m increases V increases

r is the denominator so if r increases V decreases

8 0

2 years ago

A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1

bija089 [108]

Answer:

Part a)

$\rho = 1.35 \times 10^{-5}$

Part b)

$\alpha = 1.12 \times 10^{-3}$

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

$i = 18.7 A$

V = 17.0 volts

now we will have

$V = I R$

$17.0 = 18.7 R$

R = 0.91 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho = 1.35 \times 10^{-5}$

Part b)

Now at higher temperature we have

$V = I R$

$17.0 = 17.3 R$

R = 0.98 ohm

now we know that

$R = \rho \frac{L}{A}$

$0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}$

$\rho' = 1.46 \times 10^{-5}$

so we will have

$\rho' = \rho(1 + \alpha \Delta T)$

$1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))$

$\alpha = 1.12 \times 10^{-3}$

Answer:

Part a)

$i = 1.55 A$

Part b)

$v_d = 1.4 \times 10^{-4} m/s$

Explanation:

Part a)

As we know that current density is defined as

$j = \frac{i}{A}$

now we have

$i = jA$

Now we have

$j = 1.90 \times 10^6 A/m^2$

$A = \pi(\frac{1.02 \times 10^{-3}}{2})^2$

so we will have

$i = 1.55 A$

Part b)

now we have

$j = nev_d$

so we have

$n = 8.5 \times 10^{28}$

$e = 1.6 \times 10^{-19} C$

so we have

$1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d$

$v_d = 1.4 \times 10^{-4} m/s$

8 0

3 years ago

The salinity of the oceans has been relatively constant throughout geologic time because salt is removed at the same rate at whi

tia_tia [17]

True

Explanation:

It is correct to say that the salinity of the oceans has been relatively constant throughout geologic time because salt is removed at the same rate it has been added.

Salinity is the amount of dissolved salt found in the ocean. It is the degree of saltiness of the ocean.

The rate at which salt has been added into the ocean over the years through geologic time has been very constant.
Most salts in the ocean comes from land.
Also the rate it has been removed is fairly constant.
The salinity of ocean has once been used to date the age of the earth.

learn more:

Salinity brainly.com/question/10491444

#learnwithBrainly

5 0

3 years ago

3. What would the seasons be like if Earth's orbit had the eccentricity value of Mars?

densk [106]

Answer:

123456789

Explanation:

3 0

3 years ago

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