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igomit [66]
2 years ago
9

A 29.1 liter tank contains ideal helium gas at 35.8°C and a pressure of 21.8 atm How many moles of gas are in the tank?

Physics
1 answer:
crimeas [40]2 years ago
3 0

Answer:

No. of moles, n = 25.022 moles

Given:

Volume of gas in tank, V = 29.1 l

Temperate of gas, T = 35.8^{\circ} = 273 + 35.8 = 308.8 K

Pressure of gas, P = 21.8 atm

Solution:

Making use of the ideal gas equation which given as:

PV = nRT

where

R = Rydberg's constant = 0.0821 L-atm/mol-K

Re-arranging the above formula for 'n' and putting the values in the above formula:

n = \frac{PV}{RT}

n = \frac{21.8\times 29.1}{0.0821\times 308.8}

n = 25.022

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The drawing shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel a
Pavel [41]

Answer:

F=27.39N

Explanation:

Take sum of torques at the point the step touches the wheel, that eliminates two torques

ΣT=T_{N}+T_{f}+T_{W}

Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force

T_{N}=0

The perpendicular lever arm for the F force is R-h

T_{f}=F*(r-h)

And the T of gravity according to the image

T_{W}=W*(\sqrt{r^2-(r-h)^2}

ΣT=0

T_{N}+T_{f}+T_{W}=0

F*(r-h)+W*(\sqrt{r^2-(r-h)^2}=0

F=\frac{W*(\sqrt{r^2-(r-h)^2}}{r-h}

F=\frac{24.9 N*(\sqrt{0.336^2-(0.336-0.110)^2}}{(0.336-0.11)}

F=27.39N

4 0
2 years ago
NEED ASAP PLEASE
miskamm [114]

Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.

6 0
2 years ago
A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds
Inessa05 [86]

Answer:

A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel

20miles / 5sec = 4miles /sec would be the average speed for the last 20 m

Explanation:

The answer is 4 m/s.

In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

The relation of speed (v), distance (d), and time (t) can be expressed as:

v = d/t

We need to calculate the speed of the second 5 seconds of the travel:

d = 20 m (total 30 meters - first 10 meters)

t = 5 s (time from t = 5 seconds to t = 10 seconds)

Thus:

v = 20m / 5s = 4 m/s

PLEASE GIVE BRAINIEST!! HOPE THIS HELPS

5 0
3 years ago
Wind tends to move from<br> pressure areas.<br> low, high<br> high, high<br> low, low<br> high, low
andrew-mc [135]

Answer:

high, low

Explanation:

  • Energy always flows from a higher level to a lower level.
  • It is analogous to the waterfall where waterfalls from a higher level to a lower level.
  • So in the case of the pressure of the gas, when there are any numbers of molecules in a given volume of space. The gas is said to be at high pressure.
  • When there are fewer molecules in the given volume. The gas is said to be at lower pressure.
  • Due to a large number of atoms, the high-pressure gas exerts more force on the container than the force exerted by the low-pressure gas.
  • If a hose is connected between these two containers, gas rushes from high pressure to the low pressure. Since the force exerted by the high-pressure gas is greater than that of low-pressure gas.

So, the wind tends to move from high-pressure areas to low pressure.

3 0
2 years ago
You pull a solid nickel ball with a density of 8.91 g/cm3 and a radius of 1.40 cm upward through a fluid at a constant speed of
Sunny_sXe [5.5K]

Answer:

P = 1.090\,N

Explanation:

The constant speed means that ball is not experimenting acceleration. This elements is modelled by using the following equation of equilibrium:

\Sigma F = P - W + F_{D}

\Sigma F = P - \rho \cdot V \cdot g + c\cdot v = 0

Now, the exerted force is:

P = \rho \cdot V \cdot g - c\cdot v

The volume of a sphere is:

V = \frac{4\cdot \pi}{3}\cdot R^{3}

V = \frac{4\cdot \pi}{3}\cdot (0.014\,m)^{3}

V = 1.149\times 10^{-5}\,m^{3}

Lastly, the force is calculated:

P = (8910\,\frac{kg}{m^{3}} )\cdot (1.149\cdot 10^{-5}\,m^{3})\cdot (9.81\,\frac{m}{s^{2}} )+(0.950\,\frac{kg}{s})\cdot (0.09\,\frac{m}{s} )

P = 1.090\,N

5 0
3 years ago
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