Answer:
0 N
Explanation:
Applying,
F = qvBsin∅................. Equation 1
Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.
From the question,
Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°
Substitute these values into equation 1
F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)
Since sin0° = 0,
Therefore,
F = 0 N
You would want it to be greater than D. friction force
It needs be greater than the friction applied to it.
Enough data points would have been collected when specific data for upward and downward motion are collected.
<h3>
What is a Data point?</h3>
A data point is a discrete unit of information. This information is always unique.
<h3>Free fall</h3>
An object subjected to free fall is under the influence of gravity. An object subjected has different time of motion for upward and downward motion.
Thus, we can conclude that enough data points would have been collected when specific data for upward and downward motion are collected.
Learn more about free fall here: brainly.com/question/10909077
The efficiency of the machine is defined as
Here
Work out is the work output and Work in is the work input
To find the Work in we have then
Replacing with our values
The work done by the applied force is
W = Fd
Here,
F = Force
d = Distnace
Rearranging to find F,
F = 129.77N
Therefore the force exerted on the machine after rounding off to two significant figures is 130N
