Answer:
<em>La velocidad del más rápido deberá ser de 63 Km/h</em>
Explanation:
<u>Movimiento Rectilíneo Uniforme (MRU)</u>
Un cuerpo se dice que tiene MRU cuando recorre iguales distancias en tiempos iguales y en línea recta.
Tenemos dos automóviles viajando en el mismo sentido. Uno, el más lento va por delante del otro que le ancanzará en t=6 horas una vez que supere la ventaja que le lleva el otro.
La velocidad se puede calcular con la fórmula:
Donde x es la distancia y t el tiempo que tarda en recorrerla.
El vehículo más rápido alcanzará al otro cuando logre superar los x=126 Km que le lleva. Si esto lo hace en t=6 horas, entonces la velocidad adicional que deberá desarrollar es:
Esa velocidad se suma a la del primer vehículo y tendremos la velocidad necesaria: 42 Km/h + 21 Km/h = 63 Km/h
La velocidad del más rápido deberá ser de 63 Km/h
Hello there.
<span>Which of the following would be an example of positive eugenics?
</span><span>A. Performing DNA research to eliminate breast cancer
</span>
The value of x is 40°. Because, we know that a half circle equals 180 degrees. A quarter circle equals 90 degrees. 50+40=90. The reflection area has the same degree amount, so the angle is 40 °. Let me know if this helps you!
Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2. First we must determine the final velocity:
Now we will determine the distance traveled:
Therefore, the drag racer traveled 81.83 meters in 2 seconds.
Answer:
approximately 30 degrees
Explanation:
If it takes the cannonball 2 seconds to reach the maximum height, we can use the analysis of the vertical component of the velocity and the fact that the acceleration of gravity is the one acting opposite to this initial vertical component 
of the velocity. We know as well that at the top of the trajectory, the vertical component of the velocity is zero, and then the movement starts going down in it trajectory. So, the final velocity for the first part of the ascending movement is zero, giving us the following equation for the velocity under an accelerated movement (with acceleration of gravity "g" acting):
By knowing the vertical component of the initial velocity (19.6 m/s), and the actual magnitude of the total initial velocity (40 m/s), we can calculate what angle was the initial velocity vector forming above the horizontal. We use for such the fact that the sine of the angle relates the opposite side of a right angle triangle with the hypotenuse, and solve for the angle using the arcsin function:
which tells us that the closer answer shown is 
