Esta disciplina nos permite saber y comprender cómo es el conjunto de todo lo que rodea al planeta tierra. Todas las civilizaciones que han existido a lo largo de la historia han tenido una visión de conjunto sobre el universo.
49 J is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.
Given: m = 7.3 Kg ; r = 9.4 cm = 0.094 m ; v = 3.1 m
Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation + Kinetic energy due to translation
i,e KE = 1/2*m*v2 + 1/2*I*ω2 where I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity
Now for pure rotation (without slipping) v = rω
also for the ball (solid sphere) I = 2/5*m*r2
Hence our kinetic energy becomes
KE = 1/2*m*v2 + 1/5*m*v2 = 7/10*m*v2
so KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J
Learn more about kinetic energy here
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Light travels<span> as a </span>wave<span>. But unlike sound </span>waves<span> or water </span>waves<span>, it does not need any matter or material to carry its energy along. This means that </span>light<span> can </span>travel<span> through a vacuum—a completely airless space.</span>
The answer is 8 protons hope this helps.
Explanation:
The X-component of the velocity = Vcosx. Where, V = magnitude of the velocity. The x component of velocity will depend on the diagram. It the angle is measured from the x-axis which is considered the horizontal then Vx = Vcos(theta). The magnitudes of the components of velocity v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12. Derivation of the Trajectory Formula.
y = refers to the vertical position of the object in meters. x = refers to the horizontal position of the object in meters. Horizontal velocity component: Vx = V * cos(α)
Vertical velocity component: Vy = V * sin(α)
Time of flight: t = [Vy + √(Vy² + 2 * g * h)] / g.
Range of the projectile: R = Vx * [Vy + √(Vy² + 2 * g * h)] / g.
Maximum height: hmax = h + Vy² / (2 * g)
