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Deffense [45]
3 years ago
7

When a bow is stretched back and an arrow is shot, what type of energy conversion has occurred?

Physics
1 answer:
Lelechka [254]3 years ago
6 0
D. mechanical to elastic
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There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted s
lukranit [14]

Answer:

Option B

a=19 m/s^{2}

Explanation:

Given information

Radius of container, r=12cm=12/100=0.12m

Angular velocity= 2 rev/s, converted to rad/s we multiply by 2π

Angular velocity, \omega=2*2\pi =12.56637061

We know that speed, v=r\omega

Centripetal acceleration, a=\frac {v^{2}}{r} and substituting v=r\omega we obtain that

a=r\omega^{2}

Substituting \omega for 12.56637061  and r for 0.12

a=0.12*(12.56637061)^{2}=18.94964045 m/s^{2}

Rounded off, a=19 m/s^{2}

7 0
3 years ago
A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction be
SVEN [57.7K]
The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
7 0
3 years ago
The local church is hosting a carnival which includes a bumper car ride. Bumper car A and its driver have a mass of 300 kg; bump
lukranit [14]

Answer:

a. 20 s

b. 0 m/s  

c. right

d.no its inelastic because when the car b was at rest and a was coming in at it, since b had no force what so ever car a swept it away with it moving to the right

Explanation:

im not sure though

8 0
3 years ago
A car traveling at 23m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is the acceleration?
Lena [83]

The car has an initial velocity v_0 of 23 m/s and a final velocity v of 0 m/s. Recall that for constant acceleration,

v=v_0+at

The car stops in 7 s, so the acceleration is

0\,\dfrac{\mathrm m}{\mathrm s}=23\,\dfrac{\mathrm m}{\mathrm s}+a(7\,\mathrm s)

\implies a\approx-3.29\,\dfrac{\mathrm m}{\mathrm s^2}

7 0
3 years ago
An inductor has inductance of 0.260 H and carries a current that is decreasing at a uniform rate of 18.0 mA/s.
nignag [31]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

\epsilon = -L\frac{dI}{dt}

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

\epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V

Therefore, the self-induced emf in this inductor is 4.68 mV.  

I hope it helps you!

6 0
3 years ago
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